Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion
Discussion Forum : Soil Mechanics and Foundation Engineering - Section 2 (Q.No. 7)
7.
For determing the specific gravity of soil solids, using a pycnometer of 500 cc., the following data is available : Weight of dry empty pycnometer = 125 g Weight of dried soil and pycnometer = 500 g Weight of dried soil and distilled = 850 g water filled in pycnometer up to top The specific gravity of soil soilds, is
Discussion:
13 comments Page 1 of 2.
Abhay said:
10 years ago
W1= Wt. of pycnometer = 125 g.
W2 = Wt. of pycnometer + Wt. of dry soil = 500 g.
W3 = Wt. of pycnometer + wt. of dry soil + wt. of water = 850 g.
W4 = Wt. of pycnometer + wt. of water = 500*1 + 125 = 625g,
where density of pure water = 1g/cc, volume of pycnometer = 500 cc.
G = (Wt. of dry soil)/(Wt. of water of equal volume (means equal to the volume of dry soil).
G = (W2-W1)/((W4-W1)-(W3-W2)).
Hence, G = (500-125)/((625-125)-(850-500)).
G = 375/(500-350).
G = 375/150.
G = 2.5.
W2 = Wt. of pycnometer + Wt. of dry soil = 500 g.
W3 = Wt. of pycnometer + wt. of dry soil + wt. of water = 850 g.
W4 = Wt. of pycnometer + wt. of water = 500*1 + 125 = 625g,
where density of pure water = 1g/cc, volume of pycnometer = 500 cc.
G = (Wt. of dry soil)/(Wt. of water of equal volume (means equal to the volume of dry soil).
G = (W2-W1)/((W4-W1)-(W3-W2)).
Hence, G = (500-125)/((625-125)-(850-500)).
G = 375/(500-350).
G = 375/150.
G = 2.5.
(19)
Ahmad Saadiq said:
7 years ago
Weight of soil solids = 500-125 = 375g.
The weight of water when the soil is also present in the pycnometer = 850-500 = 350g.
the Weight of water when water fills pycnometer = 500cc * 1g/cc = 500g (Since the unit weight of water is 1g/cc).
Therefore weight of equal volume of water = 500-350 = 150g.
Specific gravity = (Weight of soil solids)/(Weight of equal volume of water) = 375/150 = 2.5.
The weight of water when the soil is also present in the pycnometer = 850-500 = 350g.
the Weight of water when water fills pycnometer = 500cc * 1g/cc = 500g (Since the unit weight of water is 1g/cc).
Therefore weight of equal volume of water = 500-350 = 150g.
Specific gravity = (Weight of soil solids)/(Weight of equal volume of water) = 375/150 = 2.5.
(12)
Agilan nva said:
7 years ago
SG = Wt of dry soil/Distilled water.
Wt of dry soil = 500 - 125,
Wt of distilled water = 850 - 500,
(no need to find W4, the density of pure water or anything else).
Wt of dry soil = 500 - 125,
Wt of distilled water = 850 - 500,
(no need to find W4, the density of pure water or anything else).
(5)
Krishnaraj khatri said:
1 decade ago
S.G. = C/(B-A).
C = Oven dry weight = (500-125) = 375 g.
B = SSD weight = 500 g.
A = A1-A2 = 850-500 = 350 g.
A1 = Weight of dry soil+Water+pycnometer = 850 g.
A2= Weight of water+pycnometer = 500 g.
S.G. = C/(B-A) = 375/(500-350) = 2.5.
C = Oven dry weight = (500-125) = 375 g.
B = SSD weight = 500 g.
A = A1-A2 = 850-500 = 350 g.
A1 = Weight of dry soil+Water+pycnometer = 850 g.
A2= Weight of water+pycnometer = 500 g.
S.G. = C/(B-A) = 375/(500-350) = 2.5.
(2)
Tanmoy Karmakar said:
4 years ago
@Abhay
Thanks for explanation.
Thanks for explanation.
(2)
Anand said:
1 decade ago
Above mentioned calculation of Wcw not clear.
(1)
Priya said:
8 years ago
Thank you @Abhay.
(1)
Dilip said:
6 years ago
Thank you @Abhay.
(1)
Hatem said:
1 decade ago
Wcs=500g / Wc=125g / Wcsw=850g Wcw = 125+500 = 625g then.
Ws= Wcs-Wc = 500-125= 375g.
Gs = (Ws)/(Ws + Wcw-Wcsw).
=375/(375+625-850).
=375/150 = 2.50 (Ans. C).
Ws= Wcs-Wc = 500-125= 375g.
Gs = (Ws)/(Ws + Wcw-Wcsw).
=375/(375+625-850).
=375/150 = 2.50 (Ans. C).
MANISH AGRAHARI said:
10 years ago
W1 = 125.
W2 = 500.
W3 = 850.
W4 = 500*1+125 = 625.
Md = 375.
W4 = W3-Md+Md/G.
G = 2.5.
W2 = 500.
W3 = 850.
W4 = 500*1+125 = 625.
Md = 375.
W4 = W3-Md+Md/G.
G = 2.5.
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