Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion

2. 

For determining the moisture content of a soil sample, the following data is available Weight of container = 260 g, Weight of soil sample and = 320 g container, Weight of soil sample (dried) and = 310 g container. The moisture content of the soil sample, is

[A]. 15%
[B]. 18%
[C]. 20%
[D]. 25%

Answer: Option C

Explanation:

No answer description available for this question.

Jani said: (May 14, 2013)  
We Know that moisture content is weight of water to weight of solids. By applying that we will get the above solution.

Samba said: (Dec 21, 2013)  
Weight of conner = 260gms.
Weight of conner+soil = 320gms.
Weight of conner+dry = 310gms.

W = (Weight of solid-Weight of dry)/(Weight of dry).
= ((60-50)/(50))*100.
= 20%.

Rakesh Kumar Iiit Basar said: (Dec 29, 2013)  
Weight of solid soil sample = weight of soil sample dried with container-weight of container so.

Weight of solid soil sample = 310-260 = 50 g.

Weight of water content = weight of soil sample with water and with container-weight of soil sample dried with container.

So,
Weight of water content = 320-310 = 10 g.

Moisture content = (weight of water /weight of solid soil) *100.

So,
Moisture content = (10/50) *100 = 20%.

Honey said: (Jan 17, 2014)  
Moisture content = Weight of water/Weight of soil.

= (320-310) / (310-260).

= 20%.

Urmila Mohanty said: (Feb 25, 2015)  
For determine moisture content of the soil.

We know that the formula is weight of water/weight of solid.

So, here weight of sol sample-weight of dried soil/weight of water.

= 320-310/310-260 = 10/50.

= 0.2.

We know that water content always expressed in %.

So, 0.2*100.

= 20%.

Abhay said: (Jan 23, 2016)  
Water content = wt.of water in the soil sample/ wt.of soil(dry).

= (320-310)/(310-260).

= 10/50.

= 0.2 or 20%.

Vivek said: (Aug 5, 2017)  
Wt.of container(w1) = 260gm,
Wt.of soil+container(w2) = 320gm,
Wt.of soil (dry)+container(w3) = 310gm.
Wt.of water=320-310 = 10gm,
Wt.of soil sample = w3-w1=310-260=50gm,
Water content w = wt.of water/wt.of soil * 100.
10 * 100/50 = 20% => answer.

Srimanta said: (Sep 29, 2017)  
Wt.of container(w1) = 260gm,
Wt.of soil+container(w2) = 320gm,
Wt.of soil (dry)+container(w3) = 310gm.
Wt.of water=320-310 = 10gm,
Wt.of soil sample = w3-w1=310-260=50gm,
Water content w = (wt.of water/wt.of soil)*100.
=(10/50)*100=20%.

Kr Sheela said: (Apr 29, 2018)  
Thanks all for explaining the answer.

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