# Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion

### Discussion :: Soil Mechanics and Foundation Engineering - Section 2 (Q.No.2)

2.

For determining the moisture content of a soil sample, the following data is available Weight of container = 260 g, Weight of soil sample and = 320 g container, Weight of soil sample (dried) and = 310 g container. The moisture content of the soil sample, is

 [A]. 15% [B]. 18% [C]. 20% [D]. 25%

Explanation:

No answer description available for this question.

 Jani said: (May 14, 2013) We Know that moisture content is weight of water to weight of solids. By applying that we will get the above solution.

 Samba said: (Dec 21, 2013) Weight of conner = 260gms. Weight of conner+soil = 320gms. Weight of conner+dry = 310gms. W = (Weight of solid-Weight of dry)/(Weight of dry). = ((60-50)/(50))*100. = 20%.

 Rakesh Kumar Iiit Basar said: (Dec 29, 2013) Weight of solid soil sample = weight of soil sample dried with container-weight of container so. Weight of solid soil sample = 310-260 = 50 g. Weight of water content = weight of soil sample with water and with container-weight of soil sample dried with container. So, Weight of water content = 320-310 = 10 g. Moisture content = (weight of water /weight of solid soil) *100. So, Moisture content = (10/50) *100 = 20%.

 Honey said: (Jan 17, 2014) Moisture content = Weight of water/Weight of soil. = (320-310) / (310-260). = 20%.

 Urmila Mohanty said: (Feb 25, 2015) For determine moisture content of the soil. We know that the formula is weight of water/weight of solid. So, here weight of sol sample-weight of dried soil/weight of water. = 320-310/310-260 = 10/50. = 0.2. We know that water content always expressed in %. So, 0.2*100. = 20%.

 Abhay said: (Jan 23, 2016) Water content = wt.of water in the soil sample/ wt.of soil(dry). = (320-310)/(310-260). = 10/50. = 0.2 or 20%.

 Vivek said: (Aug 5, 2017) Wt.of container(w1) = 260gm, Wt.of soil+container(w2) = 320gm, Wt.of soil (dry)+container(w3) = 310gm. Wt.of water=320-310 = 10gm, Wt.of soil sample = w3-w1=310-260=50gm, Water content w = wt.of water/wt.of soil * 100. 10 * 100/50 = 20% => answer.

 Srimanta said: (Sep 29, 2017) Wt.of container(w1) = 260gm, Wt.of soil+container(w2) = 320gm, Wt.of soil (dry)+container(w3) = 310gm. Wt.of water=320-310 = 10gm, Wt.of soil sample = w3-w1=310-260=50gm, Water content w = (wt.of water/wt.of soil)*100. =(10/50)*100=20%.

 Kr Sheela said: (Apr 29, 2018) Thanks all for explaining the answer.