Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion
Discussion Forum : Soil Mechanics and Foundation Engineering - Section 4 (Q.No. 42)
42.
A saturated soil sample has water content of 40% and specific gravity of soil particles 2.7. The void ratio of the soil, is
Discussion:
14 comments Page 1 of 2.
Pratima Yadav said:
1 decade ago
S*e = G*w.
Where,
S = saturation (which is equal to 1 due to saturated state).
e = void ratio.
G = specific gravity.
w = water content.
e = 2.7 * 0.40 = 1.08.
The answer is 1.08.
Where,
S = saturation (which is equal to 1 due to saturated state).
e = void ratio.
G = specific gravity.
w = water content.
e = 2.7 * 0.40 = 1.08.
The answer is 1.08.
(3)
Shahul said:
7 years ago
Can anyone say how to find the porosity for the above question?
Santosh thakur said:
5 months ago
Se = wG (s = 1,w = 0.4, G = 2.7)
1.e = 0.4 * 2.7.
e = 1.08.
1.e = 0.4 * 2.7.
e = 1.08.
Jayesh said:
4 years ago
e>=1
Where the void ratio is greater or equal to 1.
Where the void ratio is greater or equal to 1.
(1)
Vishal said:
4 years ago
If n = 40%~ = 40/100 = .40.
(1-n) = 1/1+e,
=.667 = e.
(1-n) = 1/1+e,
=.667 = e.
(1)
AmAN said:
1 decade ago
S*e = G*w.
e = 2.7*0.40 = 1.08.
The answer is 1.08.
e = 2.7*0.40 = 1.08.
The answer is 1.08.
Joshita said:
4 years ago
@Zain.
Void ratio has no upper limit. i.e e>1.
Void ratio has no upper limit. i.e e>1.
Jason said:
6 years ago
Porosity is,
n = e/1+e.
n = 1.08/1+1.08.
n = 52%.
n = e/1+e.
n = 1.08/1+1.08.
n = 52%.
Manish said:
8 years ago
S*e=w*G,
e=w*G/s.
e=.40*2.7/1,
= 1.08.
e=w*G/s.
e=.40*2.7/1,
= 1.08.
(1)
Balaji said:
7 years ago
@Shahul
Porosity is 0.51, n=e/1+e.
Porosity is 0.51, n=e/1+e.
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