Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion

Discussion Forum : Soil Mechanics and Foundation Engineering - Section 1 (Q.No. 1)
1.
In a liquid limit test, the moisture content at 10 blows was 70% and that at 100 blows was 20%. The liquid limit of the soil, is
35%
50%
65%
none of these.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
123 comments Page 5 of 13.

Aita said:   7 years ago
Liquid limit(1)=70*(100÷25)^.121=82.78.
Liquid limit (2)=20*(10÷25)^.121=17.90.
Total =82.78-17.90 =64.88%.
Say 65%.

MAYANK said:   10 years ago
Correct answer is 50.1.

Simply use equation ll = -if(logx)+c.

Two equation, two unknown, solve it you will get ll = 50.1.

Yashasvi Vishwakarma said:   2 years ago
Flow index = water content at 10 no of blows - water content at 100 no of blows.

So, flow index = W10-W100 = 70-20 = 50%.
(12)

M BADRA said:   9 years ago
By interpolating the value for 25 blows the moisture content will linearly decrease up to 61.7%. Hence my answer is 61.7.

Pappu said:   1 decade ago
Liquid limit is define as water content at which the soil possesses an arbitrarily fixed small amount of shear strength.

Kishan said:   6 years ago
The correct answer is 50%, because we can't apply interpolation to a semilog graph, so need to solve using flow index.

Sharda charan said:   1 decade ago
Given;

n1=10; w1=70%.
n2=100; w2=20%.

Flow index (I)=(w1-w2)/log(n2/n1) = 50;.
wL = Ilog(n2/25)+w2;.
wL = 50.10%.

Vishal singh said:   1 decade ago
As per graph it comes near 65% and as per flow index its value come 50.10%.

Please anyone explain right one method.

Sukriti dan said:   9 years ago
As per flow index method I get 50.10. By the interpolation I get 61.6. But LIQUID LIMIT = Wn (N / 25)^n, I get 65.
(1)

Loki said:   7 years ago
50.10 is correct and one point method is not applicable because it is valid for 20 to30 blows not for 100 blows.


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