Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion
Discussion Forum : Soil Mechanics and Foundation Engineering - Section 1 (Q.No. 1)
1.
In a liquid limit test, the moisture content at 10 blows was 70% and that at 100 blows was 20%. The liquid limit of the soil, is
Discussion:
123 comments Page 4 of 13.
Rahi said:
6 years ago
70x(10/25)^0.121 = 62.65378306.
Am I right? Thanks.
Am I right? Thanks.
Anoni said:
6 years ago
Thank you @Akash.
Navya said:
6 years ago
Interpolation method is correct method for liquid limit at 25 blows. So the answer is 50%.
Ashwani bhandari said:
7 years ago
Liquid limit (1) = 70 * (10/25)^0.121 = 62.65.
Liquid limit (2) =20 * (100/25)^0.121 = 23.65.
Required limit =62.65-23.65=39.
Option D is right I think.
Liquid limit (2) =20 * (100/25)^0.121 = 23.65.
Required limit =62.65-23.65=39.
Option D is right I think.
Ganesh kawal said:
7 years ago
Plot graph liquid limit vs no of the blow.
From graph.
(70-20) ÷ (100-10)=(LL-20)÷ (100-20),
Answer is 61.
Still we assume graph is linear.
From graph.
(70-20) ÷ (100-10)=(LL-20)÷ (100-20),
Answer is 61.
Still we assume graph is linear.
SHUBHAM V said:
7 years ago
Here;
Water Content W1=70%,No. Of Blows N1=10.
Water Content W2=20%, No. Of Blows N2=100.
So For Liquid Limit,
W(L)=W(Y)(N/25)^1.21.
So For 1st 2nd Case Respectively,
W(L)1=70*(10/25)^1.21=23.09.
W(L)2=20*(100/25)^1.21=107.03.
So,
Liquid Limit=23.09+107.03/2=65.
Water Content W1=70%,No. Of Blows N1=10.
Water Content W2=20%, No. Of Blows N2=100.
So For Liquid Limit,
W(L)=W(Y)(N/25)^1.21.
So For 1st 2nd Case Respectively,
W(L)1=70*(10/25)^1.21=23.09.
W(L)2=20*(100/25)^1.21=107.03.
So,
Liquid Limit=23.09+107.03/2=65.
Nagendra said:
7 years ago
@All.
The exact Answer was obtained by interpolation of no of blows in logarithmic format right, % of water content. Hence exact Answer is 50.107 So, Option B is Right.
The exact Answer was obtained by interpolation of no of blows in logarithmic format right, % of water content. Hence exact Answer is 50.107 So, Option B is Right.
Maha said:
7 years ago
Thanks for the answer @Aakash Karoo.
Vicki said:
7 years ago
L.L = 70%-50%(0.4) = 50%.
Aita said:
7 years ago
Liquid limit(1)=70*(100÷25)^.121=82.78.
Liquid limit (2)=20*(10÷25)^.121=17.90.
Total =82.78-17.90 =64.88%.
Say 65%.
Liquid limit (2)=20*(10÷25)^.121=17.90.
Total =82.78-17.90 =64.88%.
Say 65%.
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