Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion

Discussion Forum : Soil Mechanics and Foundation Engineering - Section 1 (Q.No. 1)
1.
In a liquid limit test, the moisture content at 10 blows was 70% and that at 100 blows was 20%. The liquid limit of the soil, is
35%
50%
65%
none of these.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
123 comments Page 12 of 13.

Shubham said:   6 years ago
By interpolation, the correct answer is 50%.

Faruque Abdullah said:   6 years ago
tanβ = 0.121 is for the range of 20 to 30 blows.

As the blows number is out of this range this value should be adjusted for the individual case.
For 20 to 30 blows, tanβ = 20/(30^1.5) = 0.121.

Case-I:
tanβ = 10/(25^1.5)=0.08.
w(LL) = 70 x (10/25)^0.08 = 65.05 which is tends to 65%.

Case-II:
tanβ = 100/(25^1.5) = 0.8.
w(LL) = 20 x (100/25)^0.08 = 60.62 which is close to 65%.

KickTony said:   6 years ago
Do iteration, with N=25 blows=x.

(x1,y1) = (10,70),
(x2,y2) = (100,20),
(x,y) = (25,LL).

Substitute the values in below equation.

(y2-y1)/(x2-x1)=(y-y1)/(x-x1).
LL=65.

Rahul said:   6 years ago
Go flow index or similarities of traingle and the answer is 50.1.

Chandu said:   6 years ago
The correct Answer is 50.1.

Avnit said:   6 years ago
Flow index = (70-20)/log(100/10) = 50.
50 = (W-20)/log(100/25).
Therefore W = 50.

Md. Suruzzaman said:   6 years ago
The water content at which soil changes from liquid limit to plastic limit is called liquid limit.

Prasantambc said:   6 years ago
70% correspond.

Linear rules:- 70-(((70-20)/(10-100))*(10-25)),
=70-8.33,
= 62.67.

Biniam said:   6 years ago
Using interpolation the liquid limit at 25 no of blow is 61.67%.

Asutosh said:   6 years ago
Liquid Limit= W * (N/25)^0.121.

Where,

W = Water content at N blows.
N = No.of blows.

Liquid limit = 70*(10/25)^0121 = 89.55%.
Liquid Limit = 20*(100/25)^0.121 = 23.65%.
Required liquid limit = 88-23 = 65%.


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