Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion
Discussion Forum : Soil Mechanics and Foundation Engineering - Section 3 (Q.No. 19)
19.
A soil sample has passing 0.075 mm sieve = 60% liquid limit = 65% and plastic limit = 40%. The group index of the soil, is
Discussion:
48 comments Page 3 of 5.
Arjun said:
5 years ago
G.I = 0.2 * a +0.005 * a * c+ 0.01 * b * d.
G.I = 0.2 * 25 + 0.005 * 25 * 15 + 0.01 * 40 * 10 = 10.875.
a = P-35 = 60 - 35 = 25 ( 0-40 ) Hence adopt this value.
b = P- 15 = 60 - 15 = 45 (0-40) Hence adopt 40 .
c = LL- 40 = 65 - 40 = 15 (0-20 ) Hence adopt this value
d = PI - 10 = 65 - 40 - 10 = 15 (0-10) Hence adopt 10.
G.I = 0.2 * 25 + 0.005 * 25 * 15 + 0.01 * 40 * 10 = 10.875.
a = P-35 = 60 - 35 = 25 ( 0-40 ) Hence adopt this value.
b = P- 15 = 60 - 15 = 45 (0-40) Hence adopt 40 .
c = LL- 40 = 65 - 40 = 15 (0-20 ) Hence adopt this value
d = PI - 10 = 65 - 40 - 10 = 15 (0-10) Hence adopt 10.
RAJEEV said:
5 years ago
GI = 0.2a + 0.005ac + 0.01bd.
GI = 0.2(F-35) + 0.005(F-35)(WL-40) + 0.01(F-15)(IP-10).
GI = 0.2(F-35) + 0.005(F-35)(WL-40) + 0.01(F-15)(IP-10).
Pkota said:
5 years ago
GI = 0.2a + 0.005ac + 0.01bd.
a = F-35 = 60-35 = 25.
Which is less than 40 so a=25
b = F-15=60-15 = 45 which is greater than 40 so take b=40
c = LL-40=65-40 = 25 which must not be greater than 20 so take c=20
d = Ip-10=(LL-PL)-10 = (65-40)-10=15
GI = 0.2*25 + 0.005*25*20 + 0.01*40*15,
= 5 + 2.5 + 6 = 13.5.
a = F-35 = 60-35 = 25.
Which is less than 40 so a=25
b = F-15=60-15 = 45 which is greater than 40 so take b=40
c = LL-40=65-40 = 25 which must not be greater than 20 so take c=20
d = Ip-10=(LL-PL)-10 = (65-40)-10=15
GI = 0.2*25 + 0.005*25*20 + 0.01*40*15,
= 5 + 2.5 + 6 = 13.5.
Omi said:
4 years ago
Agree @Vivek
14.875 is the right answer.
14.875 is the right answer.
Pinkesh said:
8 years ago
GI = . 2a +. 005ac +. 01bd.
a = 25,
b = 45, bt not more than 40, = 40,
c = 25, bt nt more thn 20, = 20,
d = 15,
GI = . 2*25 +. 005*25*20 +. 01*40*15 = 13.5.
a = 25,
b = 45, bt not more than 40, = 40,
c = 25, bt nt more thn 20, = 20,
d = 15,
GI = . 2*25 +. 005*25*20 +. 01*40*15 = 13.5.
Vivek said:
1 decade ago
Pl-10 = Plasticity index-10 = 25-10 = 15.
GI = 14.875.
GI = 14.875.
Harshitha said:
10 years ago
Which answer is correct. Can I know how to solve?
Gokul said:
9 years ago
GI = 0.2a + 0.005ac + 0.01bd.
a = P - 35 = 60 - 35 = 35.
b = P - 15 = 60 - 15 = 45.
c = LL - 40 = 65 - 40 = 25.
d = PL - 10 = 40 - 10 = 30.
GI = (0.2 * 35) + (0.05 * 35 * 25) + (0.01 * 45 * 30) = 24.875.
Therefore the correct option is D.
a = P - 35 = 60 - 35 = 35.
b = P - 15 = 60 - 15 = 45.
c = LL - 40 = 65 - 40 = 25.
d = PL - 10 = 40 - 10 = 30.
GI = (0.2 * 35) + (0.05 * 35 * 25) + (0.01 * 45 * 30) = 24.875.
Therefore the correct option is D.
RANJAN PATRA,BBSR said:
9 years ago
GI = 0.2a + 0.005ac + 0.01bd.
a = P - 35 = 60 - 35 = 35.
b = P - 15 = 60 - 15 = 45.
c = LL - 40 = 65 - 40 = 25.
d = PI - 10 = 25 - 10 = 15.
GI = (0.2 * 35) + (0.05 * 35 * 25) + (0.01 * 45 * 15) = 18.125
Therefore the correct option is D.
a = P - 35 = 60 - 35 = 35.
b = P - 15 = 60 - 15 = 45.
c = LL - 40 = 65 - 40 = 25.
d = PI - 10 = 25 - 10 = 15.
GI = (0.2 * 35) + (0.05 * 35 * 25) + (0.01 * 45 * 15) = 18.125
Therefore the correct option is D.
Vishu said:
9 years ago
The correct answer is 37.
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