Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion
Discussion Forum : Soil Mechanics and Foundation Engineering - Section 3 (Q.No. 19)
19.
A soil sample has passing 0.075 mm sieve = 60% liquid limit = 65% and plastic limit = 40%. The group index of the soil, is
Discussion:
48 comments Page 2 of 5.
Danish murtaza zaidi said:
7 years ago
a = P - 35 = 60 - 35 = 25.
b = P - 15 = 60 - 15 = 45.
c = LL - 40 = 65 - 40 = 25.
d = PI - 10 = 40 - 10 = 30.
Now,
GI= 0.2a+0.005ac+0.01bd.
Thus,
GI= 0.2(25)+0.005(25)(25)+0.01(45)(30),
GI= 5+3.125+13.5,
GI= 21.625 ~ 22,
Option D is the answer.
b = P - 15 = 60 - 15 = 45.
c = LL - 40 = 65 - 40 = 25.
d = PI - 10 = 40 - 10 = 30.
Now,
GI= 0.2a+0.005ac+0.01bd.
Thus,
GI= 0.2(25)+0.005(25)(25)+0.01(45)(30),
GI= 5+3.125+13.5,
GI= 21.625 ~ 22,
Option D is the answer.
Roop Narayan (NIT SURAT) said:
9 years ago
GI = 0.2 a + 0.005 ac + 0.01 bd.
a = P - 35 = 60 - 35 = 25.
b = P - 15 = 60 - 15 = 45.
c = LL - 40 = 65 - 40 = 25.
d = PI - 10 = 40 - 10 = 30.
GI = (0.2 * 25) + (0.05 * 25 * 25) + (0.01 * 45 * 30) = 29.125.
Therefore the correct answer is (D)
a = P - 35 = 60 - 35 = 25.
b = P - 15 = 60 - 15 = 45.
c = LL - 40 = 65 - 40 = 25.
d = PI - 10 = 40 - 10 = 30.
GI = (0.2 * 25) + (0.05 * 25 * 25) + (0.01 * 45 * 30) = 29.125.
Therefore the correct answer is (D)
Gokul said:
9 years ago
GI = 0.2a + 0.005ac + 0.01bd.
a = P - 35 = 60 - 35 = 35.
b = P - 15 = 60 - 15 = 45.
c = LL - 40 = 65 - 40 = 25.
d = PL - 10 = 40 - 10 = 30.
GI = (0.2 * 35) + (0.05 * 35 * 25) + (0.01 * 45 * 30) = 24.875.
Therefore the correct option is D.
a = P - 35 = 60 - 35 = 35.
b = P - 15 = 60 - 15 = 45.
c = LL - 40 = 65 - 40 = 25.
d = PL - 10 = 40 - 10 = 30.
GI = (0.2 * 35) + (0.05 * 35 * 25) + (0.01 * 45 * 30) = 24.875.
Therefore the correct option is D.
RANJAN PATRA,BBSR said:
9 years ago
GI = 0.2a + 0.005ac + 0.01bd.
a = P - 35 = 60 - 35 = 35.
b = P - 15 = 60 - 15 = 45.
c = LL - 40 = 65 - 40 = 25.
d = PI - 10 = 25 - 10 = 15.
GI = (0.2 * 35) + (0.05 * 35 * 25) + (0.01 * 45 * 15) = 18.125
Therefore the correct option is D.
a = P - 35 = 60 - 35 = 35.
b = P - 15 = 60 - 15 = 45.
c = LL - 40 = 65 - 40 = 25.
d = PI - 10 = 25 - 10 = 15.
GI = (0.2 * 35) + (0.05 * 35 * 25) + (0.01 * 45 * 15) = 18.125
Therefore the correct option is D.
Inte said:
7 years ago
a= p-35 = 60-35=25<40 so ok
b= p- 15=60-15=45>40 so take b=40
c= LL-40=65-40=25>20 so take c=20
d=plasticity index - 10=(65-40)-10=15<20 so ok
G. I.= 0.2a+0.005ac+0.01bd.
G. I.=0.2*25+0.005*25*20+0.01*40*15.
G.I. = 13.5.
b= p- 15=60-15=45>40 so take b=40
c= LL-40=65-40=25>20 so take c=20
d=plasticity index - 10=(65-40)-10=15<20 so ok
G. I.= 0.2a+0.005ac+0.01bd.
G. I.=0.2*25+0.005*25*20+0.01*40*15.
G.I. = 13.5.
Piyush said:
5 years ago
A=60-35=25 (0 to 40),
B=60-15=45 (0 to 40) = 40,
C=65-40=25 (0 to 20) =20,
Ip=65-40=25.
D=25-10=15 (0 to 20),
G.I = 0.2*a + 0.01*b*d +0.005*a*c.
= 0.2 * 25 + 0.01 * 40 * 15 + 0.005 * 25 * 20.
= 13.5.
So, here, option D is correct.
B=60-15=45 (0 to 40) = 40,
C=65-40=25 (0 to 20) =20,
Ip=65-40=25.
D=25-10=15 (0 to 20),
G.I = 0.2*a + 0.01*b*d +0.005*a*c.
= 0.2 * 25 + 0.01 * 40 * 15 + 0.005 * 25 * 20.
= 13.5.
So, here, option D is correct.
Roop Narayan (nit surat) said:
9 years ago
GI = 0.2a + 0.005ac + 0.01bd.
a = P - 35 = 60 - 35 = 25.
b = P - 15 = 60 - 15 = 45.
c = LL - 40 = 65 - 40 = 25.
d = PI - 10 = 40 - 10 = 30.
GI = (0.2 * 25) + (0.05 * 25 * 25) + (0.01 * 45 * 30) = 29.125 ans.
a = P - 35 = 60 - 35 = 25.
b = P - 15 = 60 - 15 = 45.
c = LL - 40 = 65 - 40 = 25.
d = PI - 10 = 40 - 10 = 30.
GI = (0.2 * 25) + (0.05 * 25 * 25) + (0.01 * 45 * 30) = 29.125 ans.
Deep said:
1 decade ago
F = fineness constant.
L.l = liquid limit.
P.l = plastic limit.
Group index = (F-35)[0.2+(0.005)(Ll-40)]+0.01(F-15)(Pl-10).
G I = (60-35)[.2+(0.005)(65-40)]+0.01(60-15)(40-10).
Group index = 21.625.
L.l = liquid limit.
P.l = plastic limit.
Group index = (F-35)[0.2+(0.005)(Ll-40)]+0.01(F-15)(Pl-10).
G I = (60-35)[.2+(0.005)(65-40)]+0.01(60-15)(40-10).
Group index = 21.625.
Prakash said:
7 years ago
@Danish Murtaza Zaidi.
You are almost correct.
In the Ip {plasticity index} greater than 10% and not more than 30% ie. Range should be 1 to 20.
It means d=15-10=5.
And hence the answer is 10.125.
You are almost correct.
In the Ip {plasticity index} greater than 10% and not more than 30% ie. Range should be 1 to 20.
It means d=15-10=5.
And hence the answer is 10.125.
Afiha said:
5 years ago
I think b value is zero as b is the percentage of soil passing through 0.074 mm sieve in excess of 15%, not exceeding 55%. But given here as 60% which is greater than 55%. So, I think b=0.
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