Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion
Discussion Forum : Soil Mechanics and Foundation Engineering - Section 2 (Q.No. 31)
31.
For a clay slope of height of 10 m, the stability number is 0.05, γ = 2.0 t/m3, C = 2.5 t/m2, the critical height of the slope of the soil, is
Discussion:
5 comments Page 1 of 1.
AFZAL ANSARI said:
3 years ago
Please explain it properly.
(1)
Mann said:
10 years ago
Sn = C / Y*Fc*H.
At critical stage Fc = 1, H = Hc.
So, Sn = C /Y*Hc.
Hence, Hc = C/ Y*Sn = 2.5/2*0.05 = 25.
At critical stage Fc = 1, H = Hc.
So, Sn = C /Y*Hc.
Hence, Hc = C/ Y*Sn = 2.5/2*0.05 = 25.
(6)
Manmeet said:
1 decade ago
Hc = 2.5/(2*0.05).
HC = 25.
HC = 25.
(2)
CH SWAMY said:
1 decade ago
Hc = C/(y*Sn) y - unit weight , Sn - Stability Number.
UJWAL said:
1 decade ago
F = (C/H*Y*Sn), F = Hc/H.
Applying these two formula you will get the answer.
Applying these two formula you will get the answer.
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