Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion
Discussion Forum : Soil Mechanics and Foundation Engineering - Section 4 (Q.No. 40)
40.
The total active earth pressure due to dry back fill with no surcharge, acts at H/3 above the base of the wall and is directly proportional to
H
H2
H3.
Discussion:
9 comments Page 1 of 1.
Shuva Halder said:
4 years ago
D. H^3,
Because,
The active earth pressure with no surcharge
Pa=1/2.ka.Y.h^2 acts above the H/3.
Pa= 1/2.ka.Y.H^2.H/3.
Because,
The active earth pressure with no surcharge
Pa=1/2.ka.Y.h^2 acts above the H/3.
Pa= 1/2.ka.Y.H^2.H/3.
(1)
Paramjit Paul said:
5 years ago
Pa=1/2Ka.YH^2.
Where Pa = Active earth pressure force on a unit length of the wall.
Where Pa = Active earth pressure force on a unit length of the wall.
Abhi said:
5 years ago
Pa = Ka * H, So, Why not Option A?
Junaid khan said:
6 years ago
pa = 1/2 karH^2.
SUKUMAR said:
7 years ago
It is pressure, not active force. So, the answer is "A".
RAJU said:
8 years ago
p = 1/2 w h^2cotθ
Mmm said:
8 years ago
It is asking for pressure not thrust. It should be A.
Mahesh said:
8 years ago
p = 1/2 w h^2.
Kunal said:
9 years ago
Why not A?
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