Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion
Discussion Forum : Soil Mechanics and Foundation Engineering - Section 4 (Q.No. 19)
19.
The total weight of a pycnometer with water and oven dried soil 200 (g) is 1600 g. The pycnometer filled with water alone weighs 1500 g. The specific gravity of the soil, is
Discussion:
19 comments Page 1 of 2.
Arjun korikar said:
3 years ago
Here, 200/(1600-1500).
= 200/100,
= 2.
= 200/100,
= 2.
(1)
Surbhi said:
4 years ago
Here, G= (w2-w1)/(w2-w1)-(w3-w4).
(6)
Nurul JIST said:
5 years ago
Let,
Empty weight of pycnometer = W1.
Empty weight of pycnometer + dry soil = W2.
Empty weight of pycnometer + dry soil + water = W3.
Empty weight of pycnometer + water = W4.
W1=p.
W2=p+200.
W3=1600.
W4=1500.
G= (W2-W1)/(W3-W4) = P+200-P / 1600-1500.
= 2.
Dry Weight must be 200g.
Empty weight of pycnometer = W1.
Empty weight of pycnometer + dry soil = W2.
Empty weight of pycnometer + dry soil + water = W3.
Empty weight of pycnometer + water = W4.
W1=p.
W2=p+200.
W3=1600.
W4=1500.
G= (W2-W1)/(W3-W4) = P+200-P / 1600-1500.
= 2.
Dry Weight must be 200g.
(11)
Aswathy said:
6 years ago
For oven dry test only the formula comes as,
W = (W2 - W3/W3 - W1) x 100.
W = (W2 - W3/W3 - W1) x 100.
Faruque said:
6 years ago
Let,
The empty weight of pycnometer = W1.
The empty weight of pycnometer + dry soil = W2.
The empty weight of pycnometer + dry soil + water = W3.
The empty weight of pycnometer + water = W4.
W1=p.
W2=p+200.
W3=1600.
W4=1500.
G = (W2-ww)/[(W4-W1)-(W3-W2)].
= (P+200-P)/[(1500-P)-(1600-P-200)].
= 200/[1500-P-1600+P+200] = 200/100 = 2.
The empty weight of pycnometer = W1.
The empty weight of pycnometer + dry soil = W2.
The empty weight of pycnometer + dry soil + water = W3.
The empty weight of pycnometer + water = W4.
W1=p.
W2=p+200.
W3=1600.
W4=1500.
G = (W2-ww)/[(W4-W1)-(W3-W2)].
= (P+200-P)/[(1500-P)-(1600-P-200)].
= 200/[1500-P-1600+P+200] = 200/100 = 2.
Faruque said:
6 years ago
G = (W2-W1)/(W3-W4) = 200/ (1600-1500) = 2.
(2)
Munni said:
6 years ago
The formula for finding G by pycnometer method is---> Ws/Ws-W3-W4.
Where W3 = wt of pycnometer + wt of soil + wt of water and W4 = wt of pycnometer+wt of water.
Where W3 = wt of pycnometer + wt of soil + wt of water and W4 = wt of pycnometer+wt of water.
(2)
Suhas gotmare said:
7 years ago
W4 = 1500 w3=1600 w2 = 1600-1500 = 100,
W1=100-dry wt.
=100-20 = 80.
G = (100-80)/(1600-1500)*100 = 20%.
W1=100-dry wt.
=100-20 = 80.
G = (100-80)/(1600-1500)*100 = 20%.
Uttu said:
7 years ago
How to get w1 ?
Aru panwar said:
7 years ago
Yes, exactly the ans is 2.5.
Because G =W2-W1/(W2-W1) - (W3-W4),
=w/w-W3+W4.
Because G =W2-W1/(W2-W1) - (W3-W4),
=w/w-W3+W4.
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