Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion

Discussion Forum : Soil Mechanics and Foundation Engineering - Section 1 (Q.No. 40)
40.
A soil has bulk density 2.30 g/cm3 and water content 15 per cent, the dry density of the sample, is
1.0 g/cm2
1.5 g/cm3
2.0 g/cm3
2.5 g/cm3
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
9 comments Page 1 of 1.

E.Narasimhulu said:   10 years ago
Dry density = ratio of bulk density to water content with adding one.

D.D = 2.3/1+ 0.15 = 2 g/cm3.

M.PAGAVAN DOSS said:   9 years ago
Dry density = Grw/1+e.
Bulk density = Grw (1+w)/1+e.
rt = rd*(1+w).
rd = 2.3/1+.15 = 2gm/cubic centimeter.

Shyam sunder said:   9 years ago
Dry density = 2.3/1.15 = 2.00 gm/cm3.

SAMBA said:   7 years ago
DRY DENSITY = 2.3/1+0.15.

Skkk said:   7 years ago
Dry density = y/1+w.

=> 2.30/1+0.15.

=> 2 g/cm2.

Rohit kumar said:   7 years ago
We know that Bulk unit weigh[Yb] =Total weight/Total volume.
So, Yb = W/V =Ww + Ws/V.

NOW, Take common Ws, Hence Ws[Ww/ Ws + 1]/V.
NOW Ws / V = Yd [dry unit weight] .

Hence Yb = Yd [w = 1] because Ww/Ws = w[water content].
Now Yd = Yb /[1 + w] = 2.30/[1 + 0.15] =2 g/centi meter cube.
(1)

CHANDAN said:   6 years ago
How is it possible? Explain in detail.

Hemanta Kr Nath said:   5 years ago
Given,

The water content, W = 15%,
Bulk density, Ym = 2.30 gm/cc,
Dry density, Yd =?

We know that, Yd = 100/(100+W)*Ym.
= 100/(100+15)*2.30,
= 2.0 gm/cc.

Neha said:   2 years ago
Yd = Y/1+w.
= 2.4/1+.2.
= 2.

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