Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion
Discussion Forum : Soil Mechanics and Foundation Engineering - Section 1 (Q.No. 25)
25.
Degree of saturation of a natural soil deposit having water content 15%, specific gravity 2.50 and void ratio 0.5, is
Discussion:
12 comments Page 1 of 2.
Rajesh yadav said:
4 years ago
Se=wg or e=wg/s
0.15 * 2. 5/0.5 = 75%.
0.15 * 2. 5/0.5 = 75%.
(2)
Shubham Narayankar said:
4 years ago
Degree of saturation (Sr) = wG/e.
= 0.15 x 2.5/0.5,
= 0.75,
= 75%.
= 0.15 x 2.5/0.5,
= 0.75,
= 75%.
(6)
Engr Mohbat Marri said:
6 years ago
As
S = wG/e.
S = (15 %100x 2.5)/0.5
S = 0.75
S = 75%.
S = wG/e.
S = (15 %100x 2.5)/0.5
S = 0.75
S = 75%.
(1)
Vijaykumar vk said:
6 years ago
Se = wG.
S = wG/e.
S = 0.15 x 2.5/0.5.
S = wG/e.
S = 0.15 x 2.5/0.5.
Raju Verma said:
6 years ago
es = wG.
S = wG/e,
S = 0.15 * 2.50/0.5,
S = 75%.
S = wG/e,
S = 0.15 * 2.50/0.5,
S = 75%.
Rohit kumar said:
9 years ago
As We Know That,
Se = WG.
Where S = Degree of saturation; e = void ratio; W = water content; G = Specific gravity.
So, W = 15% = 0.15 e = 0.5 and G = 2.50
Hence S = WG/e = 0.15 * 2.50/0.5 = 0.75.
But degree of saturation is expressed in % so S = 75% answer.
Se = WG.
Where S = Degree of saturation; e = void ratio; W = water content; G = Specific gravity.
So, W = 15% = 0.15 e = 0.5 and G = 2.50
Hence S = WG/e = 0.15 * 2.50/0.5 = 0.75.
But degree of saturation is expressed in % so S = 75% answer.
(3)
Gaurav said:
9 years ago
es = wg.
And then simply,
s = we/G.
And then simply,
s = we/G.
Prathapreddy said:
9 years ago
GS = we,
S = we/g.
By substituting the values we get 75%.
S = we/g.
By substituting the values we get 75%.
MANIKANDAN.P said:
1 decade ago
s*e = w*g.
s = w*g/e.
w = 15%, g = 2.5, e = 0.5.
s = 0.15*2.5/0.5.
= 0.75.
Answer: 75%.
s = w*g/e.
w = 15%, g = 2.5, e = 0.5.
s = 0.15*2.5/0.5.
= 0.75.
Answer: 75%.
K Dharma kumar said:
1 decade ago
The relation between water content, degree of saturation, specific gravity and void ratio is given by Se=WG (or) s = WG/e.
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