Civil Engineering - RCC Structures Design - Discussion
Discussion Forum : RCC Structures Design - Section 2 (Q.No. 21)
21.
An R.C.C. column of 30 cm diameter is reinforced with 6 bars 12 mm φ placed symmetrically along the circumference. If it carries a load of 40, 000 kg axially, the stress is
Discussion:
13 comments Page 1 of 2.
RANJAN PATRA said:
9 years ago
STRESS = 40000/(3.14 * 900) * 4 = 56.
So, the answer is option A.
So, the answer is option A.
Hima Bindu said:
9 years ago
Please Explain neatly.
(1)
Sajja said:
9 years ago
It is calculated by Load/area.
Shiva said:
8 years ago
Use M20 concrete.
Cal equivalent area of concrete.
= (Ac) + (m-1) * Asc.
Load ÷ equivalent area of concrete.
Cal equivalent area of concrete.
= (Ac) + (m-1) * Asc.
Load ÷ equivalent area of concrete.
Pooja said:
8 years ago
Stress = P/A.
=40000/(3.14 x 900)/4,
= 56.
=40000/(3.14 x 900)/4,
= 56.
(2)
Rakesh kumar meena said:
8 years ago
We are not able to calculate stress without modular ratio.
(1)
Ankit Bahuguna said:
7 years ago
First, calculate the equivalent area of concrete.
Ac+(m-1)xAsc, 706.5 + (13.33-1) x 6.78 =790.
Then, 40,000/790 = 50kg/cm2.
Ac+(m-1)xAsc, 706.5 + (13.33-1) x 6.78 =790.
Then, 40,000/790 = 50kg/cm2.
Arnab said:
7 years ago
@Ankit Bahuguna.
How do you find out the value of modular ratio?
How do you find out the value of modular ratio?
Titam said:
6 years ago
Assume M20 and 415 steel for modular ratio.
The idea of assumption for m20 answer 415 is that since the question states the RCC column of 30cm, so any mix less than M20 is not a recommendation. Same goes for the use of HYSD bars i.e. 415.
The idea of assumption for m20 answer 415 is that since the question states the RCC column of 30cm, so any mix less than M20 is not a recommendation. Same goes for the use of HYSD bars i.e. 415.
Abcd said:
6 years ago
How can we find a modular ratio?
Please explain the steps.
Please explain the steps.
(2)
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