Civil Engineering - RCC Structures Design - Discussion
Discussion Forum : RCC Structures Design - Section 1 (Q.No. 8)
8.
A prestressed rectangular beam which carries two concentrated loads W at L/3 from either end, is provided with a bent tendon with tension P such that central one-third portion of the tendon remains parallel to the longitudinal axis, the maximum dip h is
Discussion:
24 comments Page 1 of 3.
Sushmitha said:
1 decade ago
Please give the explanation.
PIYUSH SINGH said:
1 decade ago
w | w
---------------------------|---------------------------
A (L/3) B (L/6) | (L/6) C (L/3) D
Reaction Ra = W.
Reaction Rb = W.
Bending Moment at Center of the Beam = [W * (L/3 + L/6) ]-[W* (L/6) ].
= WL/3.
Now Moment due to prestressing force = P*h (h= maximum dip).
Dip required => P*h = WL/3.
Therefore h = WL/3P.
(17)
Arun said:
9 years ago
Thanks @Piyush.
Lokesh said:
9 years ago
Good and thanks @Piyush Singh.
Mamun Biswal said:
8 years ago
Thanks @Piyush.
Chandru M said:
8 years ago
Thank you @Piyush Singh.
Rajesh said:
8 years ago
Thank u@piyush.
Done very cleverly....
Done very cleverly....
Manohar said:
8 years ago
Thanks @Piyush.
Somnath gorain said:
8 years ago
Thanks @Piyush.
Mriganka Roy said:
8 years ago
Thank you @Piyush.
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