Civil Engineering - RCC Structures Design - Discussion
Discussion Forum : RCC Structures Design - Section 1 (Q.No. 14)
14.
If the average bending stress is 6 kg/cm2 for M 150 grade concrete, the length of embedment of a bar of diameter d according to I.S. 456 specifications, is
Discussion:
34 comments Page 2 of 4.
Pranjal jain said:
6 years ago
According to me, it's (700/(0.87fy+1100))*d.
Vishal said:
8 years ago
It's actually development length Ld that is asked here, calculate by formula Ld= (0.87*Fy* D)/4* Tbd.
On solving this you get 087*415*D/4*1.2*1.6= 47D. This is for M20 grade.
On solving this you get 087*415*D/4*1.2*1.6= 47D. This is for M20 grade.
Sameer sopori said:
7 years ago
M15 means 15Mpa (Mega pascal).
15Mpa = 150 bar.
(because 100000 pascal equal to 1 bar).
15Mpa = 150 bar.
(because 100000 pascal equal to 1 bar).
Revathi said:
7 years ago
How this will come? Please explain.
SOUMEN DAS said:
8 years ago
The question is for M15 not M150.
For,
M15 58d
M20 47d
M25 40d
M30 38d In tension
For,
M15 58d
M20 47d
M25 40d
M30 38d In tension
Lakhan bhavnani said:
8 years ago
Please explain this question. How it is 58d?
Roy said:
8 years ago
D*130/4*0.6= 58d.
13oN/mm2=stress of mild steel,
And0.6=bond stress of M15 in wsm.
13oN/mm2=stress of mild steel,
And0.6=bond stress of M15 in wsm.
Avinash said:
9 years ago
How to calculate 58d?
Please give the correct explanation.
Please give the correct explanation.
Monika said:
1 decade ago
No, length of embedment differs with the diameter of rebar.
VR CHOWDARY said:
1 decade ago
How was it come 58d?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers