Civil Engineering - RCC Structures Design - Discussion
Discussion Forum : RCC Structures Design - Section 1 (Q.No. 14)
14.
If the average bending stress is 6 kg/cm2 for M 150 grade concrete, the length of embedment of a bar of diameter d according to I.S. 456 specifications, is
Discussion:
34 comments Page 1 of 4.
Dev Gaharwar said:
5 years ago
For Fe250 bar dia less than 20 mm:
Fst = 140 N/mm2.
And as per WSM for M15 tbd = 0.6.
Hence:
Ld = fst x d / 4 x tbd.
Ld = 140 x d / 4 x 0.6,
Ld = 58.33d.
This could be a possibility.
Fst = 140 N/mm2.
And as per WSM for M15 tbd = 0.6.
Hence:
Ld = fst x d / 4 x tbd.
Ld = 140 x d / 4 x 0.6,
Ld = 58.33d.
This could be a possibility.
(5)
Vishal said:
8 years ago
It's actually development length Ld that is asked here, calculate by formula Ld= (0.87*Fy* D)/4* Tbd.
On solving this you get 087*415*D/4*1.2*1.6= 47D. This is for M20 grade.
On solving this you get 087*415*D/4*1.2*1.6= 47D. This is for M20 grade.
Varun said:
1 decade ago
But as per the formula mentioned in IS Cods it depends on the grade of steel and bond stress. How can one comment on this without know the grade of steel?
Jagadeeshwar said:
5 years ago
For M40 and above tbd = 1.9.
And take the grade of steel 500.
Then length = 0. 87 * 500 * d/(4 * 1.9) = 58d.
And take the grade of steel 500.
Then length = 0. 87 * 500 * d/(4 * 1.9) = 58d.
(3)
Bivash said:
1 decade ago
It's depend upon bond stress, grade of steel, dia of bars.
More than Ld.
IS:456 cl:26.2.1
More than Ld.
IS:456 cl:26.2.1
Srinivas said:
10 years ago
Formula is the 0.87fyxd/4tvtbd so tv & tbd value is 1.5 then answer is 58 d I think.
Sameer sopori said:
7 years ago
M15 means 15Mpa (Mega pascal).
15Mpa = 150 bar.
(because 100000 pascal equal to 1 bar).
15Mpa = 150 bar.
(because 100000 pascal equal to 1 bar).
SOUMEN DAS said:
8 years ago
The question is for M15 not M150.
For,
M15 58d
M20 47d
M25 40d
M30 38d In tension
For,
M15 58d
M20 47d
M25 40d
M30 38d In tension
K.K MAHATA said:
7 years ago
D*140/4*0.6= 58d.
140N/mm2 = stress of HYSD,
And 0.6 = bond stress of M15 in wsm.
140N/mm2 = stress of HYSD,
And 0.6 = bond stress of M15 in wsm.
(1)
Roy said:
8 years ago
D*130/4*0.6= 58d.
13oN/mm2=stress of mild steel,
And0.6=bond stress of M15 in wsm.
13oN/mm2=stress of mild steel,
And0.6=bond stress of M15 in wsm.
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