Civil Engineering - RCC Structures Design - Discussion
Discussion Forum : RCC Structures Design - Section 1 (Q.No. 18)
18.
Dimensions of a beam need be changed if the shear stress is more than
Discussion:
31 comments Page 1 of 4.
Engr Omid said:
6 years ago
If 5 kg/sq cm then no need of bars.
If 5-20 kg/sq cm then use steel bars
If more than 20 kg/sq cm then change the section dimension.
If 5-20 kg/sq cm then use steel bars
If more than 20 kg/sq cm then change the section dimension.
(4)
Ramendra Singh said:
5 years ago
Tv = 20kg/cm^2 convert in N/mm^2, therefore, multiply by it 10^-1 and then convert into L.S.M by multiplying 1.5 =(2*1.5=3).
Tcmax = for M20 we take because minimum we take, therefore, Tcmax=2.8
Tv>Tcmax therefore redesign the section.
Tcmax = for M20 we take because minimum we take, therefore, Tcmax=2.8
Tv>Tcmax therefore redesign the section.
(3)
Kamal lochan parida said:
6 years ago
Fck means the characteristic value of concrete. Which expressed in N/square mm.
(1)
Avijit said:
6 years ago
Use the formula. Ï„ max = 0.625 * √(fck).
(1)
NITEESH patel said:
6 years ago
M 40 τ max.=2.5 N/mm^2.
M 30 τ max. =2.2 N/mm^2,
M 15 τ max.= 1.6N/mm^2,
Ans =(D)= 2.5N/mm^2.
M 30 τ max. =2.2 N/mm^2,
M 15 τ max.= 1.6N/mm^2,
Ans =(D)= 2.5N/mm^2.
(1)
Rkrana said:
7 years ago
For beam, slab, column m15 grade is used and Max shear stress for m15 grade of concrete is 25kg/cm2.
So option C is right.
So option C is right.
(1)
Dhruba said:
8 years ago
From IS 456:2000 table 20.
We have, for Concrete grade M40 and above, maximum shear stress is 4 N/mm^2.
Also from clause 40.2.3.1, we get to know that for solid slabs nominal shear stress should not exceed half the appropriate values given in Table.20. So, taking the maximum value of shear stress i.e.for M40 and above ----> 4 N/mm^2.
We will obtain its half value to be 2 N/mm^2 (or 20kg/cm^2).
We have, for Concrete grade M40 and above, maximum shear stress is 4 N/mm^2.
Also from clause 40.2.3.1, we get to know that for solid slabs nominal shear stress should not exceed half the appropriate values given in Table.20. So, taking the maximum value of shear stress i.e.for M40 and above ----> 4 N/mm^2.
We will obtain its half value to be 2 N/mm^2 (or 20kg/cm^2).
Geetesh said:
5 years ago
The dimension of beam should be changed or the beam has to be redesigned if the value of maximum Shear stress (say tau max) Exceeds 20kg/cm square.
This is the limiting value or max. Val of (tau max) for RC Beam.
This is the limiting value or max. Val of (tau max) for RC Beam.
Vikram said:
5 years ago
The method is not specified so assume wsm.
Grade not specified so assume m20( because it is the minimum grade for RCC structure)
So the answer is 1.9n/mm2.
Grade not specified so assume m20( because it is the minimum grade for RCC structure)
So the answer is 1.9n/mm2.
Amjid Ali said:
6 years ago
What is meant by (fck)? anyone tell me.
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