Civil Engineering - RCC Structures Design - Discussion
Discussion Forum : RCC Structures Design - Section 1 (Q.No. 30)
30.
According to I.S. : 456 specifications, the safe diagonal tensile stress for M 150 grade concrete, is
Discussion:
31 comments Page 2 of 4.
Achchhelal said:
9 years ago
10 percent total stress ka =15 safety factor of concrete and 3 is diagonal tensile stress.
So, 15/3 = 5.
So, 15/3 = 5.
Sushil hooda said:
8 years ago
Tensile strength= .50fcr.
Fcr=.7*150=8.57,
Tensile strength=.5*8.57,
=4.23~5.
Fcr=.7*150=8.57,
Tensile strength=.5*8.57,
=4.23~5.
Souvik said:
7 years ago
Safe diagonal tensile stress means shear stress(TC max) which is equal to 2.5 N/m^2 for M15 concrete.
Eesanya said:
6 years ago
The allowable tensile stress in mild steel bars in n/mm. sq if Dia of bar is 20mm.
Sindhu said:
4 years ago
Diagonal tension stress:large shear force & And less bending moment.
(1)
Anil babu said:
9 years ago
Tensile of concrete = 0.7fck^.5 then 0.7 * 3.87 = 2.7 N/mm2.
Roy said:
8 years ago
The units are in kg/cm^2.
So 0.7*150=6kg/cm^2.
So 0.7*150=6kg/cm^2.
Talib said:
7 years ago
Permissibl tensil stress = fck/fos = 15/3 = 5.
Suman Das said:
9 years ago
Please explain the 2nd step. How it become 5?
MD AZAM MAHTAB said:
8 years ago
Diagna tensile stress=fck/30.
=150/30=5.
=150/30=5.
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