Civil Engineering - RCC Structures Design - Discussion
Discussion Forum : RCC Structures Design - Section 1 (Q.No. 30)
30.
According to I.S. : 456 specifications, the safe diagonal tensile stress for M 150 grade concrete, is
Discussion:
31 comments Page 2 of 4.
Varsha said:
7 years ago
Thanks @Satish Suman.
Eesanya said:
6 years ago
The allowable tensile stress in mild steel bars in n/mm. sq if Dia of bar is 20mm.
Swapnil pol said:
7 years ago
@Saugat Oli.
0.35*150= 52.5.
0.35*150= 52.5.
Saugat Oli said:
7 years ago
Diagonal Tensile Strength = 1/2 * Flexural strength.
Flexural strength = 0.7 * fck,
So, Diagonal Tensile strength = 0.35* fck,
= 0.35 * 150 = 5.
Flexural strength = 0.7 * fck,
So, Diagonal Tensile strength = 0.35* fck,
= 0.35 * 150 = 5.
Shubham Chaturvedi said:
7 years ago
The tensile strength is 0.7 root over fck, it's bending tensile strength not tensile strength. Also known as flexure strength and in ques it is M15 not M150.
Safe diagonal tension = fck/3 = 15/3 = 5.
Safe diagonal tension = fck/3 = 15/3 = 5.
Talib said:
7 years ago
Permissibl tensil stress = fck/fos = 15/3 = 5.
Nancy said:
7 years ago
Thanks @Satish suman.
Nira said:
1 decade ago
Explain it please.
Souvik said:
7 years ago
Safe diagonal tensile stress means shear stress(TC max) which is equal to 2.5 N/m^2 for M15 concrete.
MD AZAM MAHTAB said:
8 years ago
Diagna tensile stress=fck/30.
=150/30=5.
=150/30=5.
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