Civil Engineering - RCC Structures Design - Discussion
Discussion Forum : RCC Structures Design - Section 1 (Q.No. 30)
30.
According to I.S. : 456 specifications, the safe diagonal tensile stress for M 150 grade concrete, is
Discussion:
31 comments Page 2 of 4.
Roy said:
8 years ago
The units are in kg/cm^2.
So 0.7*150=6kg/cm^2.
So 0.7*150=6kg/cm^2.
Sushil hooda said:
8 years ago
Tensile strength= .50fcr.
Fcr=.7*150=8.57,
Tensile strength=.5*8.57,
=4.23~5.
Fcr=.7*150=8.57,
Tensile strength=.5*8.57,
=4.23~5.
MD AZAM MAHTAB said:
8 years ago
Diagna tensile stress=fck/30.
=150/30=5.
=150/30=5.
SATISH SUMAN said:
7 years ago
Focus on the term, Safe Diagonal Tensile Stress.
1) SAFE :- F.O.S. of Concrete= Ch. Strength/1.5 = 150/1.5=100 (Its Compressive strength).
2)TENSILE STRESS :- Tensile Strength=0.7*Fck^0.5= 0.7*100^0.5=0.7*10=7 (Its Tensile stress along the neutral Axis).
3)DIAGONAL:- Diagonal Shear failure exists at 45-degree angle to the neutral axis line.
So, Corresponding Diagonal strength=Longitudinal stress*Cos45=7 cos45= 4.95 i.e 5 Ans.
1) SAFE :- F.O.S. of Concrete= Ch. Strength/1.5 = 150/1.5=100 (Its Compressive strength).
2)TENSILE STRESS :- Tensile Strength=0.7*Fck^0.5= 0.7*100^0.5=0.7*10=7 (Its Tensile stress along the neutral Axis).
3)DIAGONAL:- Diagonal Shear failure exists at 45-degree angle to the neutral axis line.
So, Corresponding Diagonal strength=Longitudinal stress*Cos45=7 cos45= 4.95 i.e 5 Ans.
(2)
Souvik said:
7 years ago
Safe diagonal tensile stress means shear stress(TC max) which is equal to 2.5 N/m^2 for M15 concrete.
Varsha said:
7 years ago
Thanks @Satish Suman.
Nancy said:
7 years ago
Thanks @Satish suman.
Talib said:
7 years ago
Permissibl tensil stress = fck/fos = 15/3 = 5.
Shubham Chaturvedi said:
7 years ago
The tensile strength is 0.7 root over fck, it's bending tensile strength not tensile strength. Also known as flexure strength and in ques it is M15 not M150.
Safe diagonal tension = fck/3 = 15/3 = 5.
Safe diagonal tension = fck/3 = 15/3 = 5.
Saugat Oli said:
7 years ago
Diagonal Tensile Strength = 1/2 * Flexural strength.
Flexural strength = 0.7 * fck,
So, Diagonal Tensile strength = 0.35* fck,
= 0.35 * 150 = 5.
Flexural strength = 0.7 * fck,
So, Diagonal Tensile strength = 0.35* fck,
= 0.35 * 150 = 5.
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