Civil Engineering - RCC Structures Design - Discussion
Discussion Forum : RCC Structures Design - Section 2 (Q.No. 47)
47.
Distribution of shear intensity over a rectangular section of a beam, follows :
Discussion:
6 comments Page 1 of 1.
Sam said:
4 years ago
Shear intensity is the shear stress over the cross-section.
Shear Stress (τ) = (3/2) * (V/A) * (1-(y/c)^2).
c is half the beam's thickness.
V is the shear force on the cross-section,
A is the area of cross-section.
y is the distance from the neutral axis.
In the case of a rectangular beam, the distribution of shear stress varies with change in y as a parabolic function.
Shear Stress (τ) = (3/2) * (V/A) * (1-(y/c)^2).
c is half the beam's thickness.
V is the shear force on the cross-section,
A is the area of cross-section.
y is the distance from the neutral axis.
In the case of a rectangular beam, the distribution of shear stress varies with change in y as a parabolic function.
Kamlesh said:
7 years ago
It may be noted that the shear stress is distributed parabolically over a rectangular cross-section.
It is maximum at y = 0 and is zero at the extreme ends.
It is maximum at y = 0 and is zero at the extreme ends.
Sankarshan Pagare said:
5 years ago
Yes, it is parabolic.
Ref. R K Bansal, Strength of Materials.
Ref. R K Bansal, Strength of Materials.
Sameer said:
5 years ago
Don't understand what question has mentioned.
Sonu said:
8 years ago
A is the correct answer.
Ref : B C Punmia.
Ref : B C Punmia.
Chhaya said:
8 years ago
How the answer is C?
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