Civil Engineering - Irrigation - Discussion

Discussion Forum : Irrigation - Section 3 (Q.No. 20)
20.
If A is the area of the surface, x is the depth of its C.G. from the surface of the water and ω is the density of water, then
total pressure on the surface is equal to ω x
depth of the point at which total pressure acts is equal to its moment of inertia divided by A x
depth of the centre of pressure is 2/3H vertically below the surface
all the above.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
3 comments Page 1 of 1.

Akshay Rana said:   4 years ago
Only C is correct.
As total pressure= ρ*g*h'*A.
And centre of pressure = (Icg/Ah')+h'.

Ambi said:   6 years ago
I think only A is correct.

Hp = H'+I Sin^2($) /AH.

Digvijay said:   6 years ago
I think Only option C is correct.

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