Civil Engineering - Irrigation - Discussion
Discussion Forum : Irrigation - Section 3 (Q.No. 1)
1.
If the straight sides of a triangular section of a lined canal with circular bottom of radius D, make an angle θ with horizontal, the hydraulic mean depth is
Discussion:
8 comments Page 1 of 1.
Rakesh said:
3 years ago
Thanks for explaining @Kajal Tomar.
Ajay Kumar Yadav said:
4 years ago
D/2 is the correct answer.
Kajal Tomar said:
6 years ago
Actually it is irrigation canal having triangular sides and circular bottom and for such canal:-
A = D"2 ( @ + cot@ )...........(1).
P = 2D ( @ + cot@ )..................(2).
therefore R = A/P = (1)/(2) = D/2.
So option B is correct
A = D"2 ( @ + cot@ )...........(1).
P = 2D ( @ + cot@ )..................(2).
therefore R = A/P = (1)/(2) = D/2.
So option B is correct
(1)
Dhananjay said:
6 years ago
Yes, you are Right @Partho.
Partho Kole said:
7 years ago
D/2 is the right answer here.
In this question, the radius is indicated by 'D', so don't take it as a diameter. Hydraulic mean radius is defined by the ratio of Area by the perimeter, if you put the right relation in between, you will definitely see the answer comes to D/2.
In this question, the radius is indicated by 'D', so don't take it as a diameter. Hydraulic mean radius is defined by the ratio of Area by the perimeter, if you put the right relation in between, you will definitely see the answer comes to D/2.
Nayan ahir said:
8 years ago
It's for diameter. In this case, the radius is D.
Shiva said:
8 years ago
Correct answer is D/4.
Narender Kumar said:
8 years ago
l think the option D is the right.
m = d/4 in circular.
m = d/4 in circular.
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