Civil Engineering - Irrigation - Discussion
Discussion Forum : Irrigation - Section 1 (Q.No. 35)
35.
If the straight sides of a triangular section of a lined canal with circular bottom of radius R, make an angle θ with horizontal, the perimeter of the canal is
Discussion:
11 comments Page 1 of 2.
Shubh said:
3 years ago
Perimetre = 2R(θ+Cotθ),
Area = R^2(θ+Cotθ),
Hydraulic radius = R=(A/P) = R/2.
Area = R^2(θ+Cotθ),
Hydraulic radius = R=(A/P) = R/2.
Samrat dhibar said:
4 years ago
The correct one is 2R(θ + tanθ).
Amjad Ali said:
6 years ago
E is the correct answer.
Because it is equal to 2R (@+cot@).
Because it is equal to 2R (@+cot@).
Basavaraj said:
7 years ago
The Correct answer is 2R(θ + cotθ).
Orai said:
7 years ago
The Correct answer should be 2R(θ + cotθ).
RAHUL said:
8 years ago
Yes, it is 2 R(θ + cotθ).
AKASH said:
8 years ago
The correct answer should be 2R(θ + cotθ).
Nisha said:
9 years ago
Thanks for the explanation @Rosh.
MAHASIN MOLLICK said:
9 years ago
Thanks @Rosh.
Rosh said:
10 years ago
Consider half portion.
For straight line portion cos θ = (x/R).
Therefore x = R.Cos θ.
Now Circular portion making angle of θ.
Length of arc = R.θ.
Therefore full length of perimeter = 2xR(θ + cos θ).
For straight line portion cos θ = (x/R).
Therefore x = R.Cos θ.
Now Circular portion making angle of θ.
Length of arc = R.θ.
Therefore full length of perimeter = 2xR(θ + cos θ).
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