Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 6 (Q.No. 31)
31.
The minimum specific energy of flow of water in open channel is : (where hc is the critical depth)
hc
hcDiscussion:
5 comments Page 1 of 1.
Dipu bunku rose said:
5 years ago
They don't say weather it is rectangular or circular so a will be the answer.
Papu said:
6 years ago
There is no mention about which type of flow.
Jadeja Mahipalsinh said:
6 years ago
This is for rectangular channel only.
If it is a triangular channel than it is 1.25 hc.
If it is a triangular channel than it is 1.25 hc.
Pandian said:
7 years ago
Ec ( specific Energy) = 3/2 yc (critical depth).
Yc = 2/3 Ec.
Yc = 2/3 Ec.
Dave said:
8 years ago
How? Explain the answer.
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