Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 1 (Q.No. 37)
37.
If D is the diameter of a pipe of length L and f is the coefficient of friction of pipe then diameter of the nozzle d is
none of these.
Discussion:
4 comments Page 1 of 1.
Khushwant rana said:
7 years ago
For maximum transmission, H=3h,
where H=Total Supply Head,
h=head lost due to friction,
H=3h.
=>v^2/2g=3 flV^2/(2gD),
where, v=velocity at the nozzle end,
V=velocity in pipe.
=>Q^2/(a^2.2g)=3flQ^2/(A^2/2gD).
where a=nozzle area,
A=area of pipe,
=>3fld^4=D^5.
=>d= (D^5/(3fl))^(1/4).
where H=Total Supply Head,
h=head lost due to friction,
H=3h.
=>v^2/2g=3 flV^2/(2gD),
where, v=velocity at the nozzle end,
V=velocity in pipe.
=>Q^2/(a^2.2g)=3flQ^2/(A^2/2gD).
where a=nozzle area,
A=area of pipe,
=>3fld^4=D^5.
=>d= (D^5/(3fl))^(1/4).
Gordon Sawian said:
4 years ago
The formula for maximum efficiency of power transmission when the nozzle is attached at exit:
fla^2/DA^2=1/2 where f= friction factor and for coefficient of friction(f') put f=4f'.
So option A is correct.
fla^2/DA^2=1/2 where f= friction factor and for coefficient of friction(f') put f=4f'.
So option A is correct.
V.V.savaliya said:
7 years ago
Why you only considered velocity head in head loss? @Khushwant Rana.
Prince said:
8 years ago
Anybody please explain it.
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