Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 2 (Q.No. 37)
37.
The discharge over a Cipolletti weir of length 2.185 m when the head over the weir is 1 m, is
Discussion:
3 comments Page 1 of 1.
Lim said:
1 month ago
Q = 2/3 * Cd * L(2g)^1/2*H^3/2.
where Cd =0.62.
Q = 2/3*2.185 * (2 * 9.81)^1/2* 1^3/2.
Q = 4.00038m^3/s.
where Cd =0.62.
Q = 2/3*2.185 * (2 * 9.81)^1/2* 1^3/2.
Q = 4.00038m^3/s.
Srinidhi said:
8 years ago
Discharge through Cipolletti weir becomes = 1.84LH^(3/2).
=1.84x2.185x1^(3/2).
=4.02m.
=1.84x2.185x1^(3/2).
=4.02m.
(5)
Ahire ramkisan said:
1 decade ago
Discharge through Cipolletti weir = 1.84LH^(3/2).
(1)
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