Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 1 (Q.No. 17)
17.
The shear stress distribution in viscous fluid through a circular pipe is :
Discussion:
48 comments Page 4 of 5.
Parth bhai said:
9 years ago
Yes, the answer should be option B.
AMAN said:
9 years ago
Shear is maximum at wall surface and velocity is maximum at center of pipe.
Shailendra kumar said:
9 years ago
Answer should be D because shear stress is 0 at centre and maximum at surface not inside the surface.
Sarath kumar said:
9 years ago
Answer 'A' because shear stress is maxed at faces n min at center as viscous flow is nothing but laminar flow.
Baloch said:
9 years ago
Stress increases linearly with distance from the centre,
i.e min at centre and max at the boundary of the pipe.
i.e min at centre and max at the boundary of the pipe.
Pavankalyan said:
8 years ago
As it is a viscous liquid it offers some resistance. So, shear stress will be min. At centre and max. At surface of the pipe. So, the answer should be B. If it is non-viscous fluid then answer is correct.
Kanishk said:
1 decade ago
The expression is given as:
Tau = del(p)/del(x) * r/2.
where r = distance from the central axis.
So the answer should be B.
Tau = del(p)/del(x) * r/2.
where r = distance from the central axis.
So the answer should be B.
Sachinreddy said:
8 years ago
Answer B is right because shear stress varies linearly from the centre of the pipe to the boundary.
It Means zero shear stress at centre & Maximum at the boundary.
It Means zero shear stress at centre & Maximum at the boundary.
Jagmohan said:
8 years ago
Shear stress is minimum at the centre.
Sarang Mote said:
8 years ago
I think the correct answer is B.
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