Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 1 (Q.No. 17)
17.
The shear stress distribution in viscous fluid through a circular pipe is :
Discussion:
48 comments Page 1 of 5.
Kanishk said:
1 decade ago
The expression is given as:
Tau = del(p)/del(x) * r/2.
where r = distance from the central axis.
So the answer should be B.
Tau = del(p)/del(x) * r/2.
where r = distance from the central axis.
So the answer should be B.
Ujwal said:
1 decade ago
Shear stress is maximum at the pipe faces and will be minimum at the center. Velocity will be max at the center and minimum at the face of pipe.
Magnus Hwosafe said:
1 decade ago
The answer is correct; the velocity is maximum @ the centre hence the shear stress being proportional to the velocity gradient is also maximum.
Prashant tomar said:
10 years ago
Shear stress is minimum in center and maximum at face.
Ejaz Ahmad said:
10 years ago
In circular pipe Shear stress is minimum at center and maximum at face inside the pipe because it varies with are i.e radius keeping dp/dx is constant but in case of velocity i.e velocity is maximum at center and minimum at face inside the pipe.
Hence answer should be B.
Hence answer should be B.
R.verman said:
9 years ago
Answer should be B.
Parth bhai said:
9 years ago
Yes, the answer should be option B.
AMAN said:
9 years ago
Shear is maximum at wall surface and velocity is maximum at center of pipe.
Shailendra kumar said:
9 years ago
Answer should be D because shear stress is 0 at centre and maximum at surface not inside the surface.
Sarath kumar said:
9 years ago
Answer 'A' because shear stress is maxed at faces n min at center as viscous flow is nothing but laminar flow.
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