Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 1 (Q.No. 17)
17.
The shear stress distribution in viscous fluid through a circular pipe is :
Discussion:
48 comments Page 2 of 5.
Sachinreddy said:
8 years ago
Answer B is right because shear stress varies linearly from the centre of the pipe to the boundary.
It Means zero shear stress at centre & Maximum at the boundary.
It Means zero shear stress at centre & Maximum at the boundary.
ROHIT SINGH BAGHEL said:
7 years ago
The Answer is correct because of the behaviour of shear stress that is one at Maximum at face and minimum at centre in constant throughout all the sections.
Ujwal said:
1 decade ago
Shear stress is maximum at the pipe faces and will be minimum at the center. Velocity will be max at the center and minimum at the face of pipe.
SK IMTIAJ ALAM said:
8 years ago
Actually, shear stress is max at inside the surface of pipe and min at the centre but distribution of shear stress is linear. So answer is (C).
Magnus Hwosafe said:
1 decade ago
The answer is correct; the velocity is maximum @ the centre hence the shear stress being proportional to the velocity gradient is also maximum.
Mesbah Ullah said:
4 years ago
The option B is correct.
As per my knowledge, shear stress is linearly increased from the centre (r=0) and maximum at boundary where (r max).
As per my knowledge, shear stress is linearly increased from the centre (r=0) and maximum at boundary where (r max).
(2)
Hussain Azam said:
7 years ago
The Correct option is B.
Because velocity is maximum at the centre whereas the shear stress is maximum at the inner surface of pipe.
Because velocity is maximum at the centre whereas the shear stress is maximum at the inner surface of pipe.
R h said:
8 years ago
Answer will be (D) none of these.
As shear stress distribution is minimum at centre and maximum at pipe wall. Don't get confused.
As shear stress distribution is minimum at centre and maximum at pipe wall. Don't get confused.
Kanishk said:
1 decade ago
The expression is given as:
Tau = del(p)/del(x) * r/2.
where r = distance from the central axis.
So the answer should be B.
Tau = del(p)/del(x) * r/2.
where r = distance from the central axis.
So the answer should be B.
RAJ said:
8 years ago
Yes, the distribution diagram is K shaped. Hence, maximum at the inside faces and zero at centre. Option B is correct.
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