Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 1 (Q.No. 17)
17.
The shear stress distribution in viscous fluid through a circular pipe is :
Discussion:
48 comments Page 2 of 5.
ROHIT SINGH BAGHEL said:
7 years ago
The Answer is correct because of the behaviour of shear stress that is one at Maximum at face and minimum at centre in constant throughout all the sections.
Sudhir said:
7 years ago
Answer should be D.
Dharmendra said:
7 years ago
Answer is B, because shear stress is min at centre and Max at inside of the surface.
Basavaraj said:
7 years ago
For shear Max at the boundary min at center where as for velocity it is parabolic section.
Asad said:
7 years ago
The Correct Answer is B. Because shear stress is maximum at distance r=D/2 from the centre of the pipe.
Ajayveer said:
7 years ago
I think Option B should be correct.
Hussain Azam said:
7 years ago
The Correct option is B.
Because velocity is maximum at the centre whereas the shear stress is maximum at the inner surface of pipe.
Because velocity is maximum at the centre whereas the shear stress is maximum at the inner surface of pipe.
Abahy Dubey said:
6 years ago
Option B is the correct answer.
PRADEEP said:
6 years ago
1. Velocity distribution is parabolic. That is maximum at the centre.
2. The shear stress distribution is zero at the centre and gradually increased though it the inner surface.
Here, "B" is the correct answer.
2. The shear stress distribution is zero at the centre and gradually increased though it the inner surface.
Here, "B" is the correct answer.
Jafar said:
5 years ago
Here, τ = -dp/dx(r/2).
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