Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 1 (Q.No. 48)
48.
A tank 4m x 3m x 2m containing an oil of specific gravity 0.83 is moved with an acceleration g/2 m sec2. The ratio of the pressures at its bottom when it is moving vertically up and down, is
Discussion:
12 comments Page 1 of 2.
Vivek Bahra said:
7 years ago
For upward acc = (p-pa)= wh(1+a/g).
For downward acc = (p-pa)= wh(1-a/g).
Substituting the value of a = g/2, the ratio of this comes out to be 3:1.
For downward acc = (p-pa)= wh(1-a/g).
Substituting the value of a = g/2, the ratio of this comes out to be 3:1.
(2)
Shama said:
7 years ago
@Monu.
Height will be same moving from the top of the tank to bottom of the tank and vice versa i.e 2m.
Height will be same moving from the top of the tank to bottom of the tank and vice versa i.e 2m.
Monu said:
8 years ago
Why height is taken same for both condition? @Alo.
Garry said:
8 years ago
The given answer is correct. It will be 3 by 1.
When the body will go upward acceleration will be G+a and when the body will go downward acceleration will be G-a.
When the body will go upward acceleration will be G+a and when the body will go downward acceleration will be G-a.
Dhanu said:
8 years ago
Correct @Abhishek.
(1)
Abhishek Anand said:
9 years ago
Effective g = g+a for upward motion.
= g-a for downward motion.
So ans = 3 : 1.
= g-a for downward motion.
So ans = 3 : 1.
R K Budumuru said:
9 years ago
Ratio of the pressures moving vertically up and down should be 1 : 3 not 3 : 1.
Aks said:
9 years ago
Good job @Alo.
ALO said:
9 years ago
Pressure ,P = Rho*g*h.
According to the condition.
When it is moving vertically up, g = ( 9.8 - 9.8/2).
when it is moving vertically down, g = ( 9.8 + 9.8/2).
Then Ratio = .83*( 9.8+9.8/2)*2 : .83*( 9.8-9.8/2)*2.
So it must me 3 : 1.
According to the condition.
When it is moving vertically up, g = ( 9.8 - 9.8/2).
when it is moving vertically down, g = ( 9.8 + 9.8/2).
Then Ratio = .83*( 9.8+9.8/2)*2 : .83*( 9.8-9.8/2)*2.
So it must me 3 : 1.
(2)
Andhokar said:
9 years ago
Please explain the solution.
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