Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 4 (Q.No. 31)
31.
If H is the depth of water retained by a vertical wall, the height of centre of pressure above the bottom is
Discussion:
35 comments Page 3 of 4.
Abhinay said:
8 years ago
It's 2h/3.
Vimesh said:
8 years ago
Not given that total pressure. Only center of pressure from water. Than h/2 is the right answer.
Nayan said:
8 years ago
It's center of pressure, H/2 to surface and H/2 to bottom.
And centroid is 2H/3 below surface.
And centroid is 2H/3 below surface.
Naveen Kallan said:
8 years ago
From the bottom it's H/3.
From the free surface of water it's 2H/3.
From the free surface of water it's 2H/3.
(3)
Sudipta said:
8 years ago
The Answer should be 2H/3. As center of pressure= H/2+{(bH^3/12)÷(bH*H/2)}=2H/3.
Akshay said:
8 years ago
CG will be at H/3. It means CP must be below the CG hence it is H/2.
Krunalsingam said:
8 years ago
I am also agree @krrish.
Jeevan said:
9 years ago
As per my knowledge, the Answer should be H/3. Center of gravity of wall may be H/2.
(1)
Siddharth said:
9 years ago
I agree with you @Krrish.
Krrish said:
9 years ago
H/3 is the answer, because pressure increase with depth of water then the pressure curve made in a triangular shape.
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