Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 4 (Q.No. 31)
31.
If H is the depth of water retained by a vertical wall, the height of centre of pressure above the bottom is
Discussion:
35 comments Page 2 of 4.
Sandeep said:
6 years ago
Both A and B are correct.
A is for triangle and B for the rectangle from the bottom.
A is for triangle and B for the rectangle from the bottom.
Sudipta said:
8 years ago
The Answer should be 2H/3. As center of pressure= H/2+{(bH^3/12)÷(bH*H/2)}=2H/3.
Jeevan said:
9 years ago
As per my knowledge, the Answer should be H/3. Center of gravity of wall may be H/2.
(1)
Rohitash Kumar said:
4 years ago
We know that h = x + Ig/Ax.
h = H/3+BH * 3/36/BH/2H/3.
h = H/3+H/6,
h = H/2.
h = H/3+BH * 3/36/BH/2H/3.
h = H/3+H/6,
h = H/2.
Naveen Kallan said:
8 years ago
From the bottom it's H/3.
From the free surface of water it's 2H/3.
From the free surface of water it's 2H/3.
(3)
Akshay said:
8 years ago
CG will be at H/3. It means CP must be below the CG hence it is H/2.
Muhammad Atiq said:
6 years ago
Pressure of water acts in a triangular manner, so its answer is H/3.
Kvl said:
7 years ago
The correct Answer is H/2 because CP is always Bellow the CG.
Suresh said:
7 years ago
From top it should be 2/3h.
From bottom 1/3 h.
From bottom 1/3 h.
Viney bhatia batala said:
5 years ago
Centre of pressure h/2.
Centre of gravity h/3.
Centre of gravity h/3.
(1)
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