Civil Engineering - Hydraulics - Discussion

Discussion Forum : Hydraulics - Section 1 (Q.No. 15)
15.
Critical depth (h) of a channel, is
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
24 comments Page 1 of 3.

Javed said:   1 decade ago
As it depends on froudes number. For critical flow froudes number is one and the depth corresponding to critical flow is called critical depth.

Froudes number = Velocity/Root of height*velocity.

Divakar said:   9 years ago
What's v2/g? Please explain.

Vishu said:   9 years ago
It is possible only for the rectangular channel.

Sreesha said:   9 years ago
As we know, that v is directly proportional to √ g*h according to Froude's law.

Ravi said:   9 years ago
Froud number equals to 1 for critical so (V/(√gh)):1.

Bapugouda said:   9 years ago
Please, anyone give me the explanation of the answer.

Abhishek Anand said:   9 years ago
The depth of water in a channel when vel of flow is critical or when the specific energy is min is called critical depth of the channel.

Critical vel of flow is the vel at which sp.energy is minimum.
Specific energy -> E=h+(v^2/2g).
For minimization, dE/dh =0.
On putting v=Q/A.
We get , 1=v^2/gh.
So, V= (gh)^1/2 or sqrt of gh.

Which is critical velocity;
So, critical depth= v^2/g.

Vaibhav Patle said:   8 years ago
No, the right answer is v2/2g.

Sandip buktare said:   8 years ago
For critical depth = v/root of height * gravity.
1 = v/root of height * gravity,
The root of height * gravity = v,
Taking square of both side.
h * g = v^2
h = v^/g.

Santhosh C said:   8 years ago
V in the above equation is critical velocity. That is velocity with respect to the critical depth of flow.


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