Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 4 (Q.No. 28)
28.
If the pressure at the inlet of a pipe is 90 kg/cm2 and pressure drop over the pipe line is 10 kg/cm2, the efficiency of transmission, is
Discussion:
9 comments Page 1 of 1.
Jagadeesh said:
3 years ago
In this question, max power transmission is not mentioned they ask efficiency of transmission.
(Output/input) *100 = 88.8%.
(Output/input) *100 = 88.8%.
(2)
Debabrata Naik said:
3 years ago
Input 90kg/cm2.
Drop-in pressure 10kg/cm3.
Output 90-10 = 80 kg/cm2.
Efficiency= (output/input)*100=88.88%.
But Max efficiency of transmission is 66.66%.
So the answer is 66.66%.
Drop-in pressure 10kg/cm3.
Output 90-10 = 80 kg/cm2.
Efficiency= (output/input)*100=88.88%.
But Max efficiency of transmission is 66.66%.
So the answer is 66.66%.
(2)
Vivek said:
4 years ago
Yes, right @Pavi.
Karpi basar said:
6 years ago
90-10/90 = 0.8888.
0.8888*100 = 88.8%.
0.8888*100 = 88.8%.
(2)
Pavi said:
6 years ago
@Navneet.
H-hf/H * 100.
H-hf/H * 100.
(1)
Kshv said:
7 years ago
But how is it possible because maximum power transmission is limited to 66.67%.
Fikie said:
8 years ago
Efficiency = (Net pressure / initial pressure )*100%.
Navneet said:
8 years ago
What's the formula?
Anand singh said:
1 decade ago
P1 = 90 kg/cm2.
P2 = 10 kg/cm2.
Efficiency = 90-10/90*100 = 88.8.
P2 = 10 kg/cm2.
Efficiency = 90-10/90*100 = 88.8.
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