Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 1 (Q.No. 32)
32.
Maximum efficiency of transmission of power through a pipe, is
Discussion:
5 comments Page 1 of 1.
MD RAFI said:
9 years ago
Efficiency = (H-hf)/H.
For max. Power transmission through pipe the condition is hf = H/3.
Substituting the value of hf in efficiency, we get max Efficiency.
Therefore, max. Effi. = [(H-H/3)/H] =1 " (1/3) = 2/3 = 66.67%.
For max. Power transmission through pipe the condition is hf = H/3.
Substituting the value of hf in efficiency, we get max Efficiency.
Therefore, max. Effi. = [(H-H/3)/H] =1 " (1/3) = 2/3 = 66.67%.
(1)
Nithu said:
8 years ago
Thank you @Md Rafi.
Sahana said:
8 years ago
Thank you @Md Rafi.
Rajesh said:
7 years ago
Thank you for explaining.
Masum said:
5 years ago
Thanks @Md Rafi.
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