Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 5 (Q.No. 18)
18.
Discharge through a totally submerged orifice, is directly proportional to
Discussion:
8 comments Page 1 of 1.
Raj said:
8 years ago
Please anybody tell me its formula.
Rishabh said:
8 years ago
The Correct option is A.
Q = Cd * b * (H2-H1)/2gh.
Q = Cd * b * (H2-H1)/2gh.
Mohan said:
8 years ago
Cd*a* √(2g(h2-h1)).
Raz said:
6 years ago
A is the correct answer.
Kailash said:
4 years ago
Which is correct A or B? Explain, please.
Anonymous said:
4 years ago
B) is the correct answer.
Because;
Discharge from Orifice
Q = a.Cd. √2gh.
Because;
Discharge from Orifice
Q = a.Cd. √2gh.
Anonymous said:
4 years ago
B) is correct.
Q=Cd*a* √(2g(h2-h1)).
a = area of orifice.
Cd = coefficient of disharge.
h1 & h2= difference in elevation of water surface.
Q=Cd*a* √(2g(h2-h1)).
a = area of orifice.
Cd = coefficient of disharge.
h1 & h2= difference in elevation of water surface.
Deepankar said:
4 years ago
The given answer is right,
Q = Cd * a * (√/2gh/), where h=difference in water level,
Ref: R.K.Bansal.
Q = Cd * a * (√/2gh/), where h=difference in water level,
Ref: R.K.Bansal.
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