Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 3 (Q.No. 9)
9.
A jet projected at an angle of 45θ, 40 m from the foot of a vertical column, just reaches the top of the column. The height of the column is
Discussion:
14 comments Page 2 of 2.
Priya said:
7 years ago
Horizontal range 40*2=u^2sin2θ/g. We get u=28.
Hmax=u^2sin(θ)^2/2g Hmax=20m.
Hmax=u^2sin(θ)^2/2g Hmax=20m.
Nikhil said:
7 years ago
40tan45°= 40m.
Viplav said:
7 years ago
40=v^2sin(90)/g.
V=20.
H=20^2 sin(45)^2/2g=15.
Answer is 15.
V=20.
H=20^2 sin(45)^2/2g=15.
Answer is 15.
Anjaligangwar said:
5 years ago
tan45° = height of the column/distance between jet and column (By Pythagoras theorem).
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