Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 3 (Q.No. 9)
9.
A jet projected at an angle of 45θ, 40 m from the foot of a vertical column, just reaches the top of the column. The height of the column is
Discussion:
14 comments Page 1 of 2.
Chandra mohan mahato said:
1 decade ago
Height of column should be 20 mtr.
Jwala said:
9 years ago
Answer 10 m.
Aditya Ch said:
9 years ago
Answer is correct.
Applying Pythagoras theorem, tan 45 = x/40, therefore x = 40 * 1 = 40.
Applying Pythagoras theorem, tan 45 = x/40, therefore x = 40 * 1 = 40.
Krishan Suthar said:
9 years ago
Yes, Correct @Aditya.
Krishan Suthar said:
9 years ago
Yes, Correct @Aditya.
Garry said:
8 years ago
The path of the particle will be a parabolic so tan θ will not be applied the correct answer from the projectile motion will come to be 20 m.
And I also agree @Mahato.
And I also agree @Mahato.
Jony said:
8 years ago
Please derive the expression @Garry.
Priya said:
7 years ago
Horizontal range 40*2=u^2sin2θ/g. We get u=28.
Hmax=u^2sin(θ)^2/2g Hmax=20m.
Hmax=u^2sin(θ)^2/2g Hmax=20m.
Nikhil said:
7 years ago
40tan45°= 40m.
Viplav said:
7 years ago
40=v^2sin(90)/g.
V=20.
H=20^2 sin(45)^2/2g=15.
Answer is 15.
V=20.
H=20^2 sin(45)^2/2g=15.
Answer is 15.
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