Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 1 (Q.No. 38)
38.
If the total head of the nozzle of a pipe is 37.5 m and discharge is 1 cumec, the power generated is
Discussion:
22 comments Page 3 of 3.
Varsha said:
9 years ago
Power = wQh.
= 9810*1*37.5.
= 367875 watts.
= 367875/736.
= 499.830.
= 9810*1*37.5.
= 367875 watts.
= 367875/736.
= 499.830.
Rishi said:
10 years ago
Power = wqH.
= 9810 x 1 x 37.5.
= 367875 watt.
= 367875 x 736 H.P.
= 499.8 H.P.
= 9810 x 1 x 37.5.
= 367875 watt.
= 367875 x 736 H.P.
= 499.8 H.P.
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