Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 1 (Q.No. 38)
38.
If the total head of the nozzle of a pipe is 37.5 m and discharge is 1 cumec, the power generated is
Discussion:
22 comments Page 1 of 3.
Deep said:
1 decade ago
P = wqh/75.
P = 1000*1*37.5/75.
P = 500.
P = 1000*1*37.5/75.
P = 500.
(4)
Rishi said:
10 years ago
Power = wqH.
= 9810 x 1 x 37.5.
= 367875 watt.
= 367875 x 736 H.P.
= 499.8 H.P.
= 9810 x 1 x 37.5.
= 367875 watt.
= 367875 x 736 H.P.
= 499.8 H.P.
Varsha said:
9 years ago
Power = wQh.
= 9810*1*37.5.
= 367875 watts.
= 367875/736.
= 499.830.
= 9810*1*37.5.
= 367875 watts.
= 367875/736.
= 499.830.
Srinu said:
9 years ago
@Varsha, Your explanation is very nice.
Ajay said:
9 years ago
Thank you all.
Rocky said:
9 years ago
Please explain it clearly.
Harsha said:
9 years ago
@Varsha.
one hp =746 watts na?
one hp =746 watts na?
Vijaya said:
9 years ago
In British system, 1HP = 746 watts.
In metric system, 1HP = 735.5watts.
In metric system, 1HP = 735.5watts.
Spal said:
8 years ago
Thank you all.
Himanshu gairola said:
8 years ago
Thanks all for giving the explanation.
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