Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 1 (Q.No. 38)
38.
If the total head of the nozzle of a pipe is 37.5 m and discharge is 1 cumec, the power generated is
Discussion:
22 comments Page 2 of 3.
Megha said:
7 years ago
What is w here?
Keshav said:
7 years ago
Power= density*Q*g*h.
= 1000*1*9.81*37.5,
= 367873 watts,
= 367873/746,
= 494 HP.
= 1000*1*9.81*37.5,
= 367873 watts,
= 367873/746,
= 494 HP.
(8)
Himanshu gairola said:
8 years ago
Thanks all for giving the explanation.
Spal said:
8 years ago
Thank you all.
Vijaya said:
9 years ago
In British system, 1HP = 746 watts.
In metric system, 1HP = 735.5watts.
In metric system, 1HP = 735.5watts.
Harsha said:
9 years ago
@Varsha.
one hp =746 watts na?
one hp =746 watts na?
Rocky said:
9 years ago
Please explain it clearly.
Ajay said:
9 years ago
Thank you all.
Srinu said:
9 years ago
@Varsha, Your explanation is very nice.
Varsha said:
9 years ago
Power = wQh.
= 9810*1*37.5.
= 367875 watts.
= 367875/736.
= 499.830.
= 9810*1*37.5.
= 367875 watts.
= 367875/736.
= 499.830.
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