Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 4 (Q.No. 47)
47.
For the two dimensional flow, the stream function is given by ψ = 2xy. The velocity at a point (3, 4) is
Discussion:
15 comments Page 1 of 2.
Mahendra said:
1 decade ago
u = dy/dx = 2y = 2*4 = 8.
v = dy/dy = 2x = 2*3 = 6.
|v| = (8^2+6^2)^1/2 = 10.
v = dy/dy = 2x = 2*3 = 6.
|v| = (8^2+6^2)^1/2 = 10.
Uday said:
8 years ago
How it will?
Please explain briefly.
Please explain briefly.
Arya said:
8 years ago
How will find velocity. I got the value of u & v?
Nayan said:
8 years ago
Differentiate the stream function with X and Y and get value of u and v.
Yatu said:
7 years ago
How it's become 10?
Anomiiee said:
7 years ago
Well said, Thanks @Mahendra.
Pawan said:
6 years ago
Thanks @Mahendra.
NILESHKUMAR Mali said:
6 years ago
D/DX=2y=2x4 = 8
D/Dy=2x=2x3 = 6.
Take under root=(√8^2+6^2)= √100=10M/sec.
D/Dy=2x=2x3 = 6.
Take under root=(√8^2+6^2)= √100=10M/sec.
Srj said:
6 years ago
For Ψ=3xy velocity=2,3.
Diff w.r.t x=3y.
Diff w.r.t y=3x.
3*2=6,
3*3=9.
√(6^2+9^2)
√(36+81)
√117.
So, the Answer is.10.82.
Diff w.r.t x=3y.
Diff w.r.t y=3x.
3*2=6,
3*3=9.
√(6^2+9^2)
√(36+81)
√117.
So, the Answer is.10.82.
Priyanka said:
5 years ago
Accurate and understandable explanation. Helpful when your have some doubt.
Thank you.
Thank you.
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