Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 5 (Q.No. 44)
44.
The depth of the centre of pressure on a vertical rectangular gate (4 m wide, 3 m high) with water upto top surface, is
Discussion:
19 comments Page 2 of 2.
Salahuddin said:
6 years ago
CG equals CP when water surface coincides the body surface. Therefore cg=cp=3/2=1.5.
Am I right?
Am I right?
Abhay said:
9 years ago
The center of pressure is located at the centroid of the rectangular shaped pressure field 2/3 from the top of the water line.
b = 4 m, d = 3 m.
Center of pressure = 2/3 d = (2/3)*3 = 2.0 m.
b = 4 m, d = 3 m.
Center of pressure = 2/3 d = (2/3)*3 = 2.0 m.
M.Atiq said:
6 years ago
Center of pressure is always below the centre of gravity and CG is located at point H/2 = 1.5m so simply we can make an idea that it will be at 2m.
Pavi said:
6 years ago
Here we can use (Ig/Ax)+x.
Aadarsh Devkate said:
7 years ago
@All.
It's very simple
Gate is vertical.
Means H = 4m.
D/2 = 4/2 = 2.
It's very simple
Gate is vertical.
Means H = 4m.
D/2 = 4/2 = 2.
Utsav said:
7 years ago
2h/3 from top.
Zuala said:
7 years ago
No @Abhay.
The centroid formula is for rectangle d/2.
The centroid formula is for rectangle d/2.
BHOOPENDER said:
8 years ago
Centre of pressure = I/ax+x.
I= bd3/12.
a=bd.
x=d/2.
I= bd3/12.
a=bd.
x=d/2.
Dinesh prasad sao said:
8 years ago
2/3 height if water is full, if not full then it's 5 of water.
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