Civil Engineering - Hydraulics - Discussion

Discussion Forum : Hydraulics - Section 5 (Q.No. 9)
9.
A rise or fall of liquid in a glass tube of a very small diameter when dipped is
directly proportional to the force per unit length of periphery
direcly proportional to the sine of the angle of contact
directly proportional to the specific weight of liquid
inversely proportional to the diameter of the glass tube.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
22 comments Page 1 of 3.

Snehal Wankhede said:   9 years ago
Option A directly proportional to σ (force/length). Inversely proportional to weight of liquid.

Santosh kr said:   8 years ago
Option D is correct because of h =4sigma cosθ divided by YD.

Hence D is correct.

Sudarshan said:   8 years ago
In question, There is a rise or fall of 'pressure'.

Ovais said:   8 years ago
A is the right answer i.e f/l.

Ranjan patel said:   8 years ago
Cause of capillarity:
The surface tension of the fluid.
Adhesion of fluid.
Sp. The weight of the fluid.
So, the answer is c.

Ritu said:   8 years ago
Answer should be option D.

Prahlad Chaudhary said:   8 years ago
Diameter is directly proportional to surface tension (σ). So correct answer is A.

SALIM MALIK said:   7 years ago
For pure water in contact with air in a clean glass tube, the capillary rise takes place with θ = 0. Mercury causes capillary depression with an angle of contact of about 1300 in a clean glass in contact with air. Since h varies inversely with D as found from Eq. ( Capillary rise (h) = 4cosθ/ρgD )an appreciable capillary rise or depression is observed in tubes of a small diameter only.

Sandeep singh said:   7 years ago
Opption A and D both are correct.

NIRANJAN said:   7 years ago
Option A & D Correct.


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