Civil Engineering - Highway Engineering - Discussion
Discussion Forum : Highway Engineering - Section 1 (Q.No. 1)
1.
A district road with a bituminous pavement has a horizontal curve of 1000 m for a design speed of 75 km ph. The super-elevation is
Discussion:
95 comments Page 8 of 10.
Elavarasy R said:
4 years ago
v^2/225R.
= 75 x 75/227 x 1000.
= 0.025.
=1in40.
= 75 x 75/227 x 1000.
= 0.025.
=1in40.
(1)
KARA LALA said:
6 years ago
GSB - Granular Sab Base.
WMM - Wet Mix Macadam.
WMM - Wet Mix Macadam.
Omkar said:
4 years ago
Yes @Yugananth
V^2/225R is the correct formula.
V^2/225R is the correct formula.
Danjah said:
9 years ago
here 1000 m is the length of curve, not radius.
Sameer naik said:
8 years ago
Why used 75% in que not mention mixed traffic?
Jatav shurjeet singh said:
9 years ago
It is the right answer, it will use v^2/225r.
BANOTH RAMESH said:
1 decade ago
ANS (A).
e = V^2/225R.
e = 0.025 = 1 in 40.
e = V^2/225R.
e = 0.025 = 1 in 40.
Prashant said:
10 years ago
1000 m is length of curve here, not radius.
RAVINDRA said:
9 years ago
The given answer is true, don't confuse it.
Biswa said:
1 decade ago
e = (0.75v)^2/Rg.
v in m/s.
Ans: 1 in 40.
v in m/s.
Ans: 1 in 40.
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