Civil Engineering - Highway Engineering - Discussion
Discussion Forum : Highway Engineering - Section 1 (Q.No. 1)
1.
A district road with a bituminous pavement has a horizontal curve of 1000 m for a design speed of 75 km ph. The super-elevation is
Discussion:
95 comments Page 7 of 10.
Arnab Chanda said:
1 decade ago
But it is not declared that 1000 m is the radius of the curve.
Naresh said:
3 years ago
e = v^2/225R.
V in kmph, R in mtrs.
75×75/225 × 1000 = 1/40.
V in kmph, R in mtrs.
75×75/225 × 1000 = 1/40.
(25)
Surya said:
1 decade ago
e = V^2/gR.
V = 75% of design speed.
V = 0.75*75.
v = V/3.2.
V = 75% of design speed.
V = 0.75*75.
v = V/3.2.
Just said:
6 years ago
75*75/(225*1000) = 75/(3*1000) = 25/1000 = 5/200 = 1/40.
(1)
Harveer singh said:
8 years ago
1 in 40 is the right answer.
V^2/125r ( f is not given).
V^2/125r ( f is not given).
Happy said:
9 years ago
But, here v^2/225 is the highest unit of super-elevation.
Mohamed Yaagob said:
10 years ago
F = 0 V = 0.75 V design speed.
E = (0.75 V)^2/(127 R).
E = (0.75 V)^2/(127 R).
Siva said:
3 years ago
Good platform. Very helpful for the competitive exams.
(2)
Timirbaran Daata said:
1 year ago
According to IRC 73-1990 Plate 1, the answer is 1:50.
Sonam phuntsho said:
7 years ago
What is the location of the road is on hilly area?
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