Civil Engineering - Highway Engineering - Discussion

Discussion Forum : Highway Engineering - Section 4 (Q.No. 29)

Highway Engineering

29.

Minimum radius of a simple circular curve deflecting through 5°, is

1618.9 m

1816.9 m

1718.9 m

1817.9 m

Answer: Option

Explanation:

No answer description is available. Let's discuss.

Discussion:

7 comments Page 1 of 1.

Shubham gour said: 5 years ago

I think The formula is R= 1746.38/D.

So, take the value 1718.9m.

Swar said: 7 years ago

Appx R = 1720/α where ;.

α =Deflection angle.

(1)

Bhattadipak said: 4 years ago

If the angle is 1 degree then it is possible.

(1)

Kishan Patel said: 6 years ago

D : 360 :: 30 : 2πR.

30X360/2 = 1718.87.

(5)

Hardik said: 7 years ago

Radius of curvature is 1718.

Utkarsh said: 8 years ago

Please provide solution.

Ravi said: 8 years ago

Please explain it.

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